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vivado [14]
3 years ago
10

How to determine if a continuous graph is a function

Mathematics
1 answer:
k0ka [10]3 years ago
3 0

Answer: A function is continuous when its graph is a single unbroken curve ... ... that you could draw without lifting your pen from the paper.

Step-by-step explanation:

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What is the y intercept of 3x62-6x+21=0
TiliK225 [7]

Answer:

(0, 207)

Step-by-step explanation:

We calculate y-intercept by substituting 0 for x.

The equation becomes:

3*62-6*(0)+21=207

y intercept is (0, 207)

3 0
3 years ago
Measurement A equals 6X - 35°
marissa [1.9K]

Answer:

............the answer is 97

6 0
3 years ago
Convert the given amount to the given unit.<br> 27 yd; ft<br> 27 yd = ft
timurjin [86]

Answer:

81 ft

Step-by-step explanation:

1 yard=3ft

27 x 3=81

So the answer is 81 ft

4 0
3 years ago
Read 2 more answers
A six-foot-tall person is standing next to a flagpole. The person is casting a shadow 1 1/2 feet in length, while the flagpole i
lara31 [8.8K]

Answer: 20 ft

This problem can be solved by the Thales’s theorem, which states:

<em>Two triangles are similar when they have equal angles and proportional sides  </em>

It should be noted that to apply Thales' Theorem, it is necessary to establish <u>the two triangles are similar</u>, that is, that t<u>hey have the corresponding angles equal or that their sides are proportional to each other.  </u>

<u />

Now, if we measure the shadow of the flagpole and the shadow of the person, <u>at the same moment</u>, we can use the first Thales' Theorem to calculate the height of the flagpole, knowing the height of the person.

In this case we have two similar triangles (Figure attached) where H is the height of the flagpole, h=6 ft is the height of the person, A=5 ft is the length of the shadow of the flagpole and a=1\frac{1}{2}=1.5 ft is the length of the shadow of the person.

Having this clear, we can write the following relation with both similar triangles:

\frac{H}{h}=\frac{A}{a}   (1)

We know all these lengths except H, which is the value we want to to find.  

So, in order to approach this problem we have to find H from equation (1):  

H=\frac{A}{a}h  

H=\frac{5 ft}{1.5 ft}(6 ft)  

Then:

H=20 ft >>>>>This is the height of the flagpole

4 0
3 years ago
Please help with #12 im confused<br> that is the key but i dont get it
Svetllana [295]

Given Equation

\boxed{ \tt \: (8 \sqrt{3}  - 2 \sqrt{2} )(8 \sqrt{3}   + 2 \sqrt{2})}

Step by step expansion:

\dashrightarrow \sf \: (8 \sqrt{3}  - 2 \sqrt{2} )(8 \sqrt{3}   + 2 \sqrt{2})

\\  \\

\dashrightarrow \sf \: (8 \sqrt{3})^{2}  - (2 \sqrt{2}  {)}^{2}

Reason:

(a + b)(a - b) = a²- b²

\\  \\

\dashrightarrow \sf \: (8 {}^{2}  \times  { \sqrt{3} }^{2} )- (2 \sqrt{2}  {)}^{2}

\\  \\

\dashrightarrow \sf \: (64  \times 3 ) - (2 \sqrt{2}  {)}^{2}

\\  \\

\dashrightarrow \sf \: (64  \times 3 ) - (2 {}^{2} \times   \sqrt{2}  {}^{2}  {)}

\\  \\

\dashrightarrow \sf \: 192- 8

\\  \\

\dashrightarrow \sf \: 184

\\  \\

~BrainlyVIP ♡

4 0
3 years ago
Read 2 more answers
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