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stiv31 [10]
2 years ago
11

An element has 3 electrons, 3 protons and 4 neutrons. What will be its atomic number and mass number? (​

Chemistry
1 answer:
stiv31 [10]2 years ago
8 0

Answer:

its atomic number will be 3 and it's mass number will be 7. it is lithium

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How to do dimensional analysis chemistry with moles?
almond37 [142]
Moles are a unit of measure used to convert between different quantities like grams, molarity or volume.

Dimensional analysis is doing math with units. They multiply, divide and cancel out just like numbers. This is why like for area of a rectangle: 2m × 3m = 6m² is in units of distance squared and volume is in units of distance cubed.

Example Chemistry question.
Now, say you have 10 grams of NaCl salt that is added to 1 L water and you want to know the concentration. You would look at the periodic table and find the atomic mass of both Sodium (Na = 23 g/mol) and Chloride (Cl = 35.5 g/mol).

Once you have the atomic mass of both elements add them together to get the atomic mass of the compound NaCl = 23 g/mol + 35.5 g/mol = 58.5 g/mol

set up the multiplication so that grams cancels out during multiplication. Like so ....
10 g *  \frac{1mol}{58.5g} = 0.17 mole..NaCl

Grams cancel leaving moles NaCl. The concentration of the solution, molarity = moles/liter
Divide 0.17 moles NaCl by 1 Liters = 0.17 Molarity NaCl

Hope this helps, let me know if you have any questions.

3 0
3 years ago
Copper has two isotopes,
Anestetic [448]

Answer:

69.152 % → 63Cu

30.848 % → 65Cu

Explanation:

As you know, the average atomic mass of an element is determined by taking the weighted average of the atomic masses of its naturally occurring isotopes.

5 0
3 years ago
A base that dissociated entirely into metal ions and hydroxide ions is known as a ________.
viva [34]
Strong base since it is completely soluble
6 0
3 years ago
Density is 6g/mL and volume is 40 mL what is the mass
myrzilka [38]

Answer:

240g

Explanation:

Using the equation m=pV, where m=mass, p=density, and V=Volume

m=(6)(40)=240

m=240

8 0
3 years ago
What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays of frequency 1.80×1015Hz ?
Soloha48 [4]

The kinetic energy of emitted electrons when cesium is exposed to UV rays of frequency 1.80 * 10 ^15 is 3.054 x 10 ^- 19 J.

Explanation:

To calculate the kinetic energy of emitted electrons,

It is given that the frequency is 1.80* 10^15 Hz

We have,

KE = E – Eo = hv –hvo

Where, h = 6.626 x 10^ - 34 Js

Given frequency = 1.4 x 10 ^ 15 Hz

vo (Threshold frequency) for cesium = 9.39 x 10 ^ 14 Hz

Applying in equation,

we get

KE = 6.626 x 10^34 (1.4 x 10^15 - 9.39 x 10^14)

KE= 3.054 x 10^-19 J

[Note: Here, threshold frequency of Cesium is not provided. Apply the correct threshold frequency from the part A]

7 0
3 years ago
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