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3 years ago

What is the freezing point, in °C, of a solution made with 1.31 mol of CHCl₃ in 530.0 g of CCl₄?

Chemistry

1 answer:

lutik1710 [3]3 years ago

7 0

Answer: 73.606 °C is the freezing point of the solution made with with 1.31 mol of CHCl3 in 530.0 g of CCl4.A

Explanation: brainliest?

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A scientist is using robots to perform thousands of experiments on different

sladkih [1.3K]

Answer: Screening

Explanation: A P E X

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3 years ago

What type of chemical bond is the strongest type of bond?

garik1379 [7]

Answer:

Covalent

Explanation:

Covalent Bonds. Another type of strong chemical bond between two or more atoms is a covalent bond. These bonds form when an electron is shared between two elements and are the strongest and most common form of chemical bond in living organisms.

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3 years ago

The following table lists the speed of sound in various materials. Use this table to answer the question.

Lynna [10]

Answer: Time taken by a sound impulse to travel through an aluminum rod 25 kilometers long is 4.9 seconds.

Solution:

Length of aluminium rod = 25 km = 25000 m (1 km=1000 m)

Time taken by sound to travel through aluminium = 5100 m/s (from the table given)

$speed=\frac{distance}{time}=\frac{25000 m}{\text{time taken}}$

time taken = $\frac{distance}{speed}=\frac{25000 m}{5100 m/s}=4.9019 seconds\approx 4.9 seconds$

Hence, the correct option is 4.9 seconds.

4 0

3 years ago

Read 2 more answers

Sort the phrases based on whether they describe or give an example of diffusion, facilitated diffusion, both, or neither. note:

Bingel [31]

Question:

a. Diffusion

b. Facilitated diffusion

c. Both

d. Neither

1. movement to area of lower concentration

2. movement across a membrane

3. steroid transport into cell

4. requires energy

5. movement assisted by proteins

6. glucose transport into cell

Answer:

The sorting is as follows

a. (1)

b. (5 and 6)

c. (1 and 2)

d. (4)

Explanation:

Diffusion is the movement of particles across a membrane from a high concentration region to one with a lower concentration of the diffusing substance

Here we have the correct sorting as follows

a. Diffusion

3. steroid transport into cell

b. Facilitated diffusion

5. movement assisted by proteins

6. glucose transport into cell

c. Both

1. movement to area of lower concentration

2. movement across a membrane

d. Neither

4. requires energy

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3 years ago

A chemist prepares a solution of copper(II) fluoride by measuring out of copper(II) fluoride into a volumetric flask and filling

Simora [160]

The question is incomplete, here is the complete question.

A chemist prepares a solution of copper(II) fluoride by measuring out 0.0498 g of copper(II) fluoride into a 100.0mL volumetric flask and filling the flask to the mark with water.

Calculate the concentration in mol/L of the chemist's copper(II) fluoride solution. Round your answer to 3 significant digits.

<u>Answer:</u> The concentration of copper fluoride in the solution is $4.90\times 10^{-3}mol/L$

<u>Explanation:</u>

To calculate the molarity of solute, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Given mass of copper (II) fluoride = 0.0498 g

Molar mass of copper (II) fluoride = 101.54 g/mol

Volume of solution = 100.0 mL

Putting values in above equation, we get:

$\text{Molarity of copper (II) fluoride)=\frac{0.0498\times 1000}{101.54\times 100.0}\\\\\text{Molarity of copper (II) fluoride}=4.90\times 10^{-3}mol/L$

Hence, the concentration of copper fluoride in the solution is $4.90\times 10^{-3}mol/L$

4 0

3 years ago