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3 years ago

Can bees really fly if so why

1 answer:

3 0

The swirls of air at the edge of a bee's wing enable the insect to angle its wing more sharply toward the sky, improving the flow of air over the wing. It's this higher wing angle that gives bees, fruit flies and even humming birds enough lift to fly.

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Soil that are light in color have a great amount of humus in them. True or False

GaryK [48]

Answer:

please the answer Is false

6 0

3 years ago

A chemical combination of two or more atoms is a(n) .

irinina [24]

Answer:

Molecule

Explanation:

Its simple definition

6 0

3 years ago

Read 2 more answers

How many Protons, electrons, and neutrons are in Dysprosium? EASY POINTS?

Nadya [2.5K]

Answer:

Number of Protons - 66

Number of Neutrons - 97

Number of Electrons - 66

Explanation:

You're welcome :3

4 0

4 years ago

Use MO diagrams to place B2+, B2, and B2- in order of (a) decreasing bond energy; (b) decreasing bond length.

shepuryov [24]

We use the MO diagram for a homonuclear diatomic species (since C and N are neighbours, we treat them as the "same").

The first two electrons contribute to bonding. The next two are anti-bonding.

The next six contribute to bonding, and the following six are anti-bonding.

So, if we start with CN+, which has 4+5-1 (8) valence electrons, we note that the first two electrons contribute to bonding, while the next two cancel this out; the next four contribute to bonding, so the bond order is 4/2 = 2.

If we add one more electron to get CN, there are now 5 bonding electrons, giving bond order 5/2=2.5.

Adding one more to give CN- would give the bond order 6/2 = 3. (If we added more electrons, each one would lower the bond order.)

Given a series of molecules with identical skeletal structures, the one with the highest bond order has the highest bond energy:

CN+ < CN < CN-

Lewis structures will verify that CN- has a triple bond, but they do not work particularly well for CN+ and CN.

learn more about bond orders at

brainly.com/question/9713842

#SPJ1

3 0

2 years ago

What amount of heat is released when the temperature of 450.0 g of a

Molodets [167]

Answer:

$\boxed {\boxed {\sf 4038.48 \ Joules}}$

Explanation:

Since we are given the mass, specific heat, and change in temperature, we should use this formula for heat:

$q=mc\Delta T$

The substance's mass is 450.0 grams, the specific heat is 1.264 J/g°C, and the change in temperature is 7.1 °C.

$m= 450.0 \ g \\c= 1.264 \ J/g \textdegree C\\\Delta T= 7.1 \ \textdegree C$

Substitute the values into the formula.

$q= (450.0 \ g)(1.264 \ J/g \textdegree C)(7.1 \ \textdegree C)$

Multiply the first 2 values together. The grams will cancel out.

$q= 568.8 \ J/ \textdegree C (7.1 \ \textdegree C)$

Multiply again. This time, the degrees Celsius cancel out.

$q= 4038.48 \ J$

4038.48 Joules of heat energy are released.

5 0

3 years ago