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koban [17]
3 years ago
13

Can bees really fly if so why

Chemistry
1 answer:
Helga [31]3 years ago
3 0
The swirls of air at the edge of a bee's wing enable the insect to angle its wing more sharply toward the sky, improving the flow of air over the wing. It's this higher wing angle that gives bees, fruit flies and even humming birds enough lift to fly.
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In which species does phosphorous have the highest oxidation number?
nignag [31]

the compounds in which phosphorous posses the highest possible oxidation have to mention here.

The species in which phosphorous have the highest oxidation state are: H₃PO₄, P₂O₅, PCl₅

The possible oxidation state of phosphorous is III and V. The highest oxidation state is V. There are several compounds in which phosphorous posses the +5 oxidation state. Like- Phosphoric acid (H₃PO₄), phosphorous pentoxide (P₂O₅), Phosphorous chloride (PCl₅) etc.

The oxidation state of an element depends upon the valence electron the valence shell of phosphorous is 3s² 3p³. Thus there are 5 electrons, as it has vacant 3d orbital thus it can easily form compound having +5 oxidation state.

7 0
2 years ago
How many neutrons are found in each atom of boron?
Vadim26 [7]
There are 6 neutrons in an atom of Boron
5 0
3 years ago
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Why are noble metals for example Rhodium, Palladium, Platinum, and Iridium largely used in chemical manufacturing as heterogeneo
Elanso [62]

They are also called the noble gases or inert gases. They are virtually unreactive towards other elements or compounds. They are found in trace amounts in the atmosphere. Their elemental form at room temperature is colorless, odorless and monatomic gases. They also have full octet of eight valence electrons in their highest orbitals so they have a very little tendency to gain or lose electrons to form ions or share electrons with other elements in covalent bonds.

4 0
3 years ago
How many molecules are in 10 moles of Hydrogen?
vivado [14]

Answer:3.2

Mass:32

Molecular weight: 10

Moles: 3.2

8 0
3 years ago
What is the change in enthalpy associated with the combustion of 530 g of methane (CH4)?Report your answer in scientific notatio
Veseljchak [2.6K]

Answer:

-3.0\times 10^4 kJ is the change in enthalpy associated with the combustion of 530 g of methane.

Explanation:

CH_4+2O_2\rightarrow CO_2+2H_2O,\Delta H_{comb}=-890.8 kJ/mol

Mass of methane burnt = 530 g

Moles of methane burnt = \frac{530 g}{16 g/mol}=33.125 mol

Energy released on combustion of 1 mole of methane = -890.8 kJ/mol

Energy released on combustion of 33.125 moles of methane :

-890.8 kJ/mol\times 33.125 mol=-29,507.75 kJ=-2.950775\times 10^4 kJ

-2.950775\times 10^4 kJ\approx -3.0\times 10^4 kJ

-3.0\times 10^4 kJ is the change in enthalpy associated with the combustion of 530 g of methane.

7 0
3 years ago
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