Answer:
3.10g
Explanation:
Please see the attached picture for the full solution.
The problem above can be solved using M1V1=M2V2 where M1 is the concentration of the concentrated, V1 is the volume of the concentrated solution, M2 is the concentration of the Dilute Solution, V2 is the Volume of the dilute solution. Hence,
(3.0 M)(V2)=(250 mL)(1.2M)
V2 (3.0)= 300
V2= 100 mL
Therefore, you need 100 mL of 3.0 M HCl to form a 250 mL of 1.2 M HCl.
57.1g * 6.022*10^23 / 22.9 * 2 = 7.51*10^23 molecules
NO3- will affect the pH of a solution. The ion will decrease the pH of a neutral solution. No3- ion is a conjugate base of a strong acid, therefore, if it added to a neutral solution of pH 7, it will change the pH of the solution by decreasing the pH, that is, the solution will become acidic in nature.
