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3 years ago

How many milliliters of a 3.0 M HCL solution are required to make 250.0 millimeters of 1.2 M HCL?

1 answer:

7 0

The problem above can be solved using M1V1=M2V2 where M1 is the concentration of the concentrated, V1 is the volume of the concentrated solution, M2 is the concentration of the Dilute Solution, V2 is the Volume of the dilute solution. Hence,

(3.0 M)(V2)=(250 mL)(1.2M)
V2 (3.0)= 300
V2= 100 mL

Therefore, you need 100 mL of 3.0 M HCl to form a 250 mL of 1.2 M HCl.

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Temperature also affects the motion of atoms in a gas. Given what you know about temperature, pressure, and volume, which statem

vampirchik [111]

Answer:

C) As a gas is heated, the pressure decreases.

Explanation:

From the choices given, the statement that "as a gas is heated, the pressure decreases is false".

When gases are heated, their molecules expands and the volume of the gas increases. In a fixed container, the pressure of the gases will also increases.

Gases lack internal cohesion and very weak to no intermolecular forces binding them together.
When they are subjected to heat, they gain more energy(kinetic energy) which causes them to begin to spread out.
Thus, they take up even more space allowing volume to increase appreciably.

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2 years ago

For an exothermic reaction, what effect will increasing the temperature have on the equilibrium?

VLD [36.1K]

The result of an exothermic reaction is released heat. According the Le Chatelier's principle, increasing the temperature means increasing the amount of products. This means that there will be more reactants left at equilibrium.

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3 years ago

A student uses visible spectrophotometry to determine the concentration of CoCl2(aq) in a sample solution. First the student pre

gladu [14]

Answer:

Explanation:

2.60 g of CoCl2 was dissolved in water to make 100 mL of solution.

Number of moles of CoCl2 dissolved = mass/molar mass

= 2.60/130

= 0.02 mole

Molar concentration of solutions = number of moles/volume (dm3)

= 0.02/0.1

= 0.200 M

Hence, the molar concentration of thesolution is 0.200 molar.

Correct option = A

3 0

3 years ago

the density of gold is 19.3 g/cm3. a 3.4 mg piece of gold is hammered into a square that is 8.6 x 10-6 cm thick. what is the len

faltersainse [42]

Answer:

The length of a side of the square is 4.53 cm

Explanation:

Volume (V) = mass/density

mass = 3.4 mg = 3.4/1000 = 0.0034 g

density = 19.3 g/cm^3

V = 0.0034/19.3 = 1.76×10^-4 cm^3

Volume = area × thickness

Area = volume/thickness = 1.76×10^-4/8.6×10^-6 = 20.48 cm^2

Length of one side of the square = sqrt(area of square) = sqrt(20.48 cm^2) = 4.53 cm

3 0

3 years ago

For an alloy that consists of 93.1 g copper, 111.7 g zinc, and 4.0 g lead, what are the concentrations of (a) Cu, (b) Zn, and (c

Andrew [12]

Answer:

(a) weight percent of Cu = 44.59%

(b) weight percent of Zn = 53.49%

Explanation:

Given: Alloy contains- Cu=93.1 g, Zn=111.7 g, Pb=4.0 g

Therefore, the total mass of the alloy (m) = mass of Cu (m₁) + mass of Zn (m₂)+ mass of Pb (m₃)

m= 93.1 g + 111.7 g + 4.0 g = 208.8 g

(a) weight percent of Cu = (m₁ ÷ m)× 100% = (93.1 g ÷ 208.8 g)× 100% =44.59%

(b) weight percent of Zn = (m₂ ÷ m)× 100% = (111.7 g ÷ 208.8 g)× 100% =53.49%

5 0

3 years ago