When writing the electron configuration for an element in the d block you have to remember to lower the energy level by 1.
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Answer:
pH = 5.47
Explanation:
The equilibrium that takes place is:
HIO ↔ H⁺ + IO⁻
Ka = = 2.3 * 10⁻¹¹
At equilibrium:
- [HIO] = 0.5 M - x
- [H⁺] = x
- [IO⁻] = x
<u>Replacing those values in the equation for Ka and solving for x:</u>
Then [H⁺]=3.39 * 10⁻⁶, thus pH = 5.47