A rack of 15 billiard balls is shown. If one ball is selected at random, determine the odds against it containing a number grea
1 answer:
Using the probability and odds concepts, it is found that the odds against it containing a number greater than or equal to 7 is .
- A probability is the <u>number of desired outcomes divided by the number of total outcomes</u>.
- An odd is the <u>number of desired outcomes divided by the number of non-desired outcomes</u>.
In the rack, there are 15 balls, numbered from 1 to 15. Of those, <u>6 are less than 7</u>(against it containing a number greater than or equal to 7 is equivalent to it containing a number less than 7), thus:
- There are 6 desired outcomes.
- There are 9 non-desired outcomes.
The odd is:
The odds against it containing a number greater than or equal to 7 is .
A similar problem is given at brainly.com/question/21094006
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