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sladkih [1.3K]
3 years ago
12

50 POINTS A cell phone company charges a monthly base fee for a phone plan with a limit of 500 text messages. A $0.10 fee is cha

rged for each message beyond the limit. An equation that models the month's total cost, y, based on the number of text messages beyond the limit, x, is shown below. The rate of change in the equation represents how much the changes based on the . The monthly base fee is .
Mathematics
1 answer:
serg [7]3 years ago
8 0

Answer:

y = n +.1x

Step-by-step explanation:

y is the total. x is how much over 500 texts she is. n is her base for 500 texts and less.

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1k + 9&gt;30 <br><br> Plis ayúdenme
Leni [432]

Answer:

Step-by-step explanation:

1k +9 > 30

1k +9 -9 > 30 -9

1k > 21

k > 21

7 0
3 years ago
Brad has two alloys containing copper and silver. Alloy A contains 50% pure silver, and alloy B contains 75% pure silver. He wan
oee [108]

Answer:

I think the answer would be

Alloy A 30%

Alloy B 40%

The reason I say that is because Alloy B has a higher amount of pure silver so yeah

I hope this helps mark me brainliest and tell me if I'm wrong please so Then I could fix it.

P.S. Wegnerkolmp2741o is gonna answer so I would go with his


8 0
3 years ago
Read 2 more answers
Can someone help me
sergij07 [2.7K]

Answer:

1)  (c)∠ G = 34°

2) (a)  x = 33°

3) (d) The perpendicular segments are  JM, KL, PQ AND NR.

Step-by-step explanation:

Here in the given questions:

1)  p II r

⇒ ∠ G  = 34°  (ALTERNATE EXTERIOR ANGLES)

Hence, the measure of  ∠ G = 34°

2) In the given triangle:

The measure of exterior angle is always the sum of interior opposite angles.

⇒ Here, x + 72°  = 105°

or, x = 105° - 72° =   33°   , or x = 33°

3) The given plane in the cube is JKPN

The segments which have J , K , P and N as their one vertex are perpendicular to the given plane.

Hence, the segments are  JM, KL, PQ AND NR.

7 0
4 years ago
. Explain why projectile motion, such as kicking a ball off the top of building, has a curved path. Identify the two forces invo
deff fn [24]

The initial kick is the first force applied to the ball. It sends the ball up into the air (at some angle). If gravity wasn't present, then the ball would go upward forever in a straight line. However, gravity is the second force pulling down on the ball. This explains why the ball hits some peak point or highest point before it is pulled to the ground. Overall, the path the ball takes is a parabolic arch.

In short, the two forces are the initial kick and gravity.

side note: technically air resistance (aka air friction or drag) is a force being applied since the air pushes against the ball to slow it down, but often air resistance is really complicated and beyond the scope of many math courses. So your teacher may want you to ignore air resistance.

Another note: the initial kick is a one time force that only happens at the beginning. Once the ball is in the air, that force isn't applied anymore. In contrast, the force of gravity is always present and always pulling down. It's probably incredibly obvious, but it's worth pointing out this difference.

4 0
4 years ago
What is the sum of<br> Σ4(0.5) -1,<br> n=1<br> O S=1.5<br> O S = 2<br> O S = 4.5<br> O S = 8
slamgirl [31]

Answer:

S=4.5

Step-by-step explanation:

dxxzzzzzzzzzzzzzz---

3 0
3 years ago
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