Answer:
The pH of the buffer is 7.0 and this pH is not useful to pH 7.0
Explanation:
The pH of a buffer is obtained by using H-H equation:
pH = pKa + log [A⁻] / [HA]
<em>Where pH is the pH of the buffer</em>
<em>The pKa of acetic acid is 4.74.</em>
<em>[A⁻] could be taken as moles of sodium acetate (14.59g * (1mol / 82g) = 0.1779 moles</em>
<em>[HA] are the moles of acetic acid (0.060g * (1mol / 60g) = 0.001moles</em>
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Replacing:
pH = 4.74 + log [0.1779mol] / [0.001mol]
<em>pH = 6.99 ≈ 7.0</em>
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The pH of the buffer is 7.0
But the buffer is not useful to pH = 7.0 because a buffer works between pKa±1 (For acetic acid: 3.74 - 5.74). As pH 7.0 is out of this interval,
this pH is not useful to pH 7.0
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Explanation:
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Water molecules have space in between them. They are not packed tightly in liquid form. So the dissolved sugar molecules fill the intermolecular space in between the water molecules. This is why you cannot really see a rise in water level.
Answer:
29.9 moles
2C²H¹⁰ needs 13 moles of O²
4.6 C⁴H¹⁰ needs X moles of O²
X= 13× 4.6 ÷ 2 = 59.8 ÷ 2 = 29.9 moles
