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ivanzaharov [21]
3 years ago
8

When sugar crystals dissolve in water the level of water does not rise appreciably why?

Chemistry
1 answer:
Vlad [161]3 years ago
6 0
Water molecules have space in between them. They are not packed tightly in liquid form. So the dissolved sugar molecules fill the intermolecular space in between the water molecules. This is why you cannot really see a rise in water level.  
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How many grams of KNO3 are required to prepare 0.250 L of 0.70 M solution?​
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Answer:

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Density of a piece of wood that has a measurement of 24 cm3 and 768 g
Brut [27]

Answer:

<h3>The answer is 32 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 768 g

volume = 24 cm³

We have

density =  \frac{768}{24}  \\

We have the final answer as

<h3>32 g/cm³</h3>

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The iodide ion reacts with hypochlorite ion (the active ingredient in chlorine bleaches) in the following way:
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Explanation:

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           OCl^{-} + I^{-} \rightarrow OI^{-1} + Cl^{-1}

So, when we double the amount of hypochlorite or iodine then the rate of the reaction will also get double. And, this reaction is "first order" with respect to hypochlorite and iodine.

Hence, equation for rate law of reaction will be as follows.

              Rate = K \times [OCl^{-}] \times [l^{-}]

(b)  Since, the rate equation is as follows.

                    Rate = K [OCl^{-}][l^{-}]

Let us assume that ([OCl^{-}] = [l^{-}])

Putting the given values into the above equation as follows.

             1.36 \times 10^{-4} = K \times (1.5 \times 10^{-3})^2

            1.36 \times 10^{-4} = K \times (2.25 \times 10^{-6})

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                Rate = K [OCl^{-}][l^{-}]

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                        = 6.52 \times 10^{5}

Therefore, rate when [OCl^{-}] = 1.8 \times 10^{3} M and [I^{-}]= 6.0 \times 10^{4} M is  6.52 \times 10^{5}.

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Answer:

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