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Sedaia [141]
2 years ago
7

Which representation shows y as a function of x?

Mathematics
2 answers:
AveGali [126]2 years ago
8 0
I think the correct answer A is a function
Aleks [24]2 years ago
6 0
Option A would be a function because the input (x) must be paired to directly 1 unique output (y). However the outputs can be paired to different inputs.
You might be interested in
Use synthetic division to solve (x^3+1)/(x-1). What is the quotient?
Sav [38]

Answer:

  x^2 +x +1

Step-by-step explanation:

See below for the tableau. The quotient is x^2 +x +1.

___

The remainder is 2.

7 0
3 years ago
Find the area of the blue sector of the circle. Round to the nearest hundredth.
Varvara68 [4.7K]
A diagram must be associated with the question above. Based on what I researched, this is what I got.

The blue sector of the circle is 120 degrees.

area of the blue sector = 1/3  of pi * 2^2
                                     = 4.19cm2

I hope this answer helps.
8 0
3 years ago
I need help, I dont know how to convert ratios into decimals and percentages [EX: write the ratio 5 to 8 in a decimal/percent]​
Anon25 [30]
Fractions are just unsimplified numbers. For example 5/8 is just 5 divided by 8 so 0.625. To find the percent from that you move the decimal two places to the right making it 62.5%. Hope this helps!
5 0
3 years ago
Round to the nearest hundredth (Geometric Series problem)
WITCHER [35]

Answer:

15.98

Step-by-step explanation:

∑₁¹⁰ 8(\frac{1}{4} )^{n-1}

=8[1+\frac{1}{4} +\frac{1}{16} + ........ +t_{10}]

We have to use the formula of sum of a G.P. series with common ratio r < 1.

If the first term is a, the common ratio is r and the number of terms is n then the sum [a + ar + ar² + ar³ + ......... up to n terms] is given by  

[a \times\frac{1-r^{n} }{1-r}]

= 8[1 \times \frac{1-\frac{1}{2^{10} } }{1-\frac{1}{2} } ]

= 15.98 (Answer)

4 0
3 years ago
Pls give correct answer for brainiest
GREYUIT [131]

Answer:

C. -8/3

Step-by-step explanation:

3t + 4 = -4

3t = -4 - 4

3t = -8

t = -8/3

3 0
3 years ago
Read 2 more answers
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