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MrMuchimi
2 years ago
14

Astronomers measure large distances in light-years. One light-year is the distance that light can travel in one year, or approxi

mately 5,880,000,000,000 miles. Suppose a star is 13.6 light-years from Earth. In scientific notation, how many miles away is it? Plaese answer in scientific notation?
Mathematics
1 answer:
maksim [4K]2 years ago
6 0

13.6 = 10, 3, 0.6

thats the answer

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Find the indefinite integral using the substitution provided.
Nady [450]

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=======================================================

Explanation:

Start with the equation u = e^{2x}+10

Apply the derivative and multiply both sides by 7 like so

u = e^{2x}+10\\\\\frac{du}{dx} = 2e^{2x}\\\\7\frac{du}{dx} = 7*2e^{2x}\\\\7\frac{du}{dx} = 14e^{2x}\\\\7du = 14e^{2x}dx\\\\

The "multiply both sides by 7" operation was done to turn the 2e^(2x) into 14e^(2x)

This way we can do the following substitutions:

\displaystyle \int \frac{14e^{2x}}{e^{2x}+10}dx\\\\\\\displaystyle \int \frac{1}{e^{2x}+10}14e^{2x}dx\\\\\\\displaystyle \int \frac{1}{u}7du\\\\\\\displaystyle 7\int \frac{1}{u}du\\\\\\

Integrating leads to

\displaystyle 7\int \frac{1}{u}du\\\\\\7\text{Ln}\left(u\right)+C\\\\\\7\text{Ln}\left(e^{2x}+10\right)+C\\\\\\

Be sure to replace 'u' with e^(2x)+10 since it's likely your teacher wants a function in terms of x. Also, do not forget to have the plus C at the end. This is a common mistake many students forget to do.

To verify the answer, you can apply the derivative to it and you should get back to the original integrand of \frac{14e^{2x}}{e^{2x}+10}

4 0
2 years ago
Suppose a house costs $270,000 appreciates by 5% each year. In about how many years will the house be worth $350000?
Vikki [24]
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n =  log 1.296296 / log 1.05 = 5.3 years answer
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3 years ago
Please help me with this homework
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The third one

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y+1=-2(x-3) becomes y=-2x+5

Then just graph it.

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3 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
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X - 3, where x represent the floor you are on currently.

Hope this helps!
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