Answer:
84 is the highest possible course average
Step-by-step explanation:
Total number of examinations = 5
Average = sum of scores in each examination/total number of examinations
Let the score for the last examination be x.
Average = (66+78+94+83+x)/5 = y
5y = 321+x
x = 5y -321
If y = 6, x = 5×6 -321 =-291.the student cannot score -291
If y = 80, x = 5×80 -321 =79.he can still score higher
If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.
If y= 100
The average cannot be 100 as student cannot score 179(maximum score is 100)
Answer:
144
Step-by-step explanation
8x6=48
48 divided by 2=24
24x2=48
4x10=40
8x4=32
4x6=24
add them all together so 48+40+32+24=144
The answer is going to be6/8
For easier calculation,
convert 4years 8months into months. This would give you 56months.
Amit is 56months old.
4 units/proportion =56
1 unit=56/4
5unit=56/4 ×5(simplify)
Answer:
(-3,-1)
Step-by-step explanation:
When you graph it on a graphing paper, you can see that the graph touches it but barely
