Answer:
6
Step-by-step explanation:
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Answer:
Step-by-step explanation:
J is a tangent to the circle and it is at right angle,
So applying Pythagorean theorem
HK² = KJ² + HJ²
HK² = 8²+ 15²
HK² = 64 + 225
HK² = 289
HK = √289
HK = 17 mi
1 subtract 1 2m - 1 = 3m
<span>2 subtract 2 2m = 1 + m </span>
<span>3 subtract m m - 1 = 2 </span>
<span>4 add 2 + m = 3 </span>
<span>5 subtract 2m -2 + m = 1 </span>
<span>6 add 1 3 = 1 + m
1.5.
2.4
3.1
42
56
63</span>
Ok so we'll go ahead and solve for y first - we just need to get it alone on one side of the equal sign
Step 1: subtract 2x from each side
2x - 7y - 2x = 19 - 2x
This cancels out the 2x on the left, giving us
-7y = 19 - 2x
Step 2: divide both sides by -7
=
+ 
This gives us
y = -19/7 + 2x/7
That should be your answer for the first question. Now solving the next parts are easy. All you need to do is plug in x.
When x = -3
y = -19/7 + 2x/7
y = -19/7 + 2(-3)/7
y = -19/7 - 6/7
y = -25/7
When x = 0
y = -19/7 + 2x/7
y = -19/7 + 2(0)/7
y = -19/7
When x = 3
y = -19/7 + 2x/7
y = -19/7 + 2(3)/7
y = -19/7 + 6/7
y = -13/7
Hope that helps! Feel free to ask if I can help with anything else :)