Answer:
We conclude that the percentage of blue candies is equal to 29%.
Step-by-step explanation:
We are given that in a random selection of 100 colored candies, 28% of them are blue. The candy company claims that the percentage of blue candies is equal to 29%.
Let p = <u><em>population percentage of blue candies</em></u>
So, Null Hypothesis,
: p = 29% {means that the percentage of blue candies is equal to 29%}
Alternate Hypothesis,
: p
29% {means that the percentage of blue candies is different from 29%}
The test statistics that will be used here is <u>One-sample z-test for</u> <u>proportions</u>;
T.S. =
~ N(0,1)
where,
= sample proportion of blue coloured candies = 28%
n = sample of colored candies = 100
So, <u><em>the test statistics</em></u> = ![\frac{0.28-0.29}{\sqrt{\frac{0.29(1-0.29)}{100} } }](https://tex.z-dn.net/?f=%5Cfrac%7B0.28-0.29%7D%7B%5Csqrt%7B%5Cfrac%7B0.29%281-0.29%29%7D%7B100%7D%20%7D%20%7D)
= -0.22
The value of the z-test statistics is -0.22.
<u>Also, the P-value of the test statistics is given by;</u>
P-value = P(Z < -0.22) = 1 - P(Z
0.22)
= 1 - 0.5871 = 0.4129
Now, at a 0.10 level of significance, the z table gives a critical value of -1.645 and 1.645 for the two-tailed test.
Since the value of our test statistics lies within the range of critical values of z, <u><em>so we insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.
Therefore, we conclude that the percentage of blue candies is equal to 29%.