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2 years ago

Please help,will give Brainliest

Mathematics

2 answers:

Arada [10]2 years ago

8 0

Question 5 is 410$ I’m sorry don’t know the rest

Bess [88]2 years ago

4 0

Answer:

question 1. 50$

Question 2. 50 + 25

Question 3. Every week I get 25$

Question 4. 305$

Question 5. 410$

Step-by-step explanation:

I am SOOOO sorry if some of them are wrong :( I'm not the best at this kind of stuff

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In two or three sentences explain how you would solve for the real solutions of the following equation: please help asap!!

g100num [7]

the real solutions for the equation $x^{3}=-64$ are -

$x=4,2+-2\sqrt{3i}$

Step-by-step explanation:

$x^{3}$ = $- 64$

$x^{3} +64$ = 0

We can write 64 as $4^{3}$

$x^{3}$ + $4^{3}$ = 0

using the identity ( $x^{3}+y^{3} = (x+y)(x^{2} -xy+y^{2} )$ )

we get,

= $(x+4) (x^{2} -x*4+4^{2} )$

= $(x+4)(x^{2} -4x+16)$ ....................(1)

solving the quadratic equation ,

$x^{2} -4x+16$ =0

solutions of this quadratic equation can be obtained by

$x=-b +- \sqrt{b^{2}-4ac } /2a$

let use y for factors

$x=-(-4x)+-\sqrt{(-4x^{2} )-4*x^{2} *16} / 2*x^{2}$

$x=4x+-\sqrt{16x^{2} -64x^{2} } /2x^{2}$

$x=4+-\sqrt{16-64}/2$

$x=4+-4\sqrt{3i} /2$

$x=2+-2\sqrt{3i}$ ..................(2)

from the equation 1 we have,

$x-4=0$

which gives solution $x=4$

and from equation 2 we got $x=2+-2\sqrt{3i}$

so the real solutions for the equation $x^{3}=-64$ are -

$x=4,2+-2\sqrt{3i}$

3 0

2 years ago

Solve 5 + 44 = 2 + r

pickupchik [31]

Okay the answer is r=47
Let's solve your equation step-by-step.5+44=2+r
Step 1: Simplify both sides of the equation.5+44=2+r
Simplify:49=r+2
Step 2: Flip the equation.r+2=49
Step 3: Subtract 2 from both sides.r+2−2=49−2r=47
Answer:r=47
Hope this helps!:)

6 0

2 years ago

Read 2 more answers

In the local frisbee league, teams have 7 members and each of the 4 teams takes turns hosting tournaments. At each tournament, e

mars1129 [50]

There are 4 teams in total and each team has 7 members. One of the team will be the host team.

Tournament committee will be made from 3 members from the host team and 2 members from each of the three remaining teams. Selecting the members for tournament committee is a combinations problem. We have to select 3 members out 7 for host team and 2 members out of 7 from each of the remaining 3 teams.

So total number of possible 9 member tournament committees will be equal to:

$7C3 \times 7C2 \times 7C2 \times 7C2\\ \\ = 324135$

This is the case when a host team is fixed. Since any team can be the host team, there are 4 possible ways to select a host team. So the total number of possible 9 member tournament committee will be:

$9 \times 324135\\ \\ =2917215$

Therefore, there are 2917215 possible 9 member tournament committees

8 0

2 years ago

Use the relationship between the angles in the figure to answer the question.

grigory [225]

Answer:

x = 52, A.

Step-by-step explanation:

The two angles across from each other are both acute angles, which means that considering their positioning, they're gonna equal the same in degrees. If the question were asking to find the value of x on one of the obtuse angles, your answer would be B, considering both of those lines would equal 180 degrees.

Hope that helps!

3 0

3 years ago

Question 5

ladessa [460]

Answer:

C is correct

Step-by-step explanation: c is correct great job

7 0

2 years ago