Liters
Grams
Degrees Celsius
The other answer choices are from the imperial system
Gravity is the correct answer.
Answer:
Explanation:
The question here is that if sneezy hands from a similar rope while delivering presents at the earth's equator, what will be the tension in the rope be. Here is the solution:The tension on the rope when it is at pole, T= 455 NTo find, the tension, t= mgTo solve for mass, m= t/g. Substituting this we have, m=455/9.8. m=46.43 kgAssume that the downwards acceleration is, a= -46.43 m/s^2.T = mg + maT = (46.43 kg) ( 9.8 m/s^2) - (46.43 kg) (-46.43 m/s^2)T = 455.01 kg-m/s^2 - -2155.74 kg-m/s^2T = 2610.75 kg-m/s^2 = 2610.75 N
Mass of Tracey M1 = 32 kg
Mass of Jonas M2 = 45 kg
Initially both were at rest
so V1i = V2i =0
after pushing each other Jonas speed V2f = 0.80 m/s
we need to find out final speed of Tracy
Here we can use momentum conservation as no external force is acting here
M1V1i + M2V2i = M1V1f + M2V2f
32(0) + 45(0) = 32 V1f + 45(0.80)
0 = 32 V1f + 36
-36 = 32 V1f
V1f = - 1.125 m/s
negative sign shows that Tracy will move opposite to the Jonas
so answer in two significant figure would be
V1f = 1.1 m/s
