An object in motion will continue to move in the same direction and with the same speed unless acted upon by an unbalanced force. states that forces occur as equal and opposite pairs. The strength of the force is related to the mass of the objects and the distance between them.
Distance fallen = 1/2 ( V initial + V final ) *t
We know
a = -9.8 m/s2
t=120s
To find distance fallen, we need to find V final
Use the equation
V final = V initial + a*t
Substitute known values
V final = 0 + (-9.8)(120)
V final = -1176 m/s
Then plug known values to distance fallen equation
Distance fallen = 1/2 ( 0 + 1176 )(120)
= 1/2(1776)(120)
=106,560 m
This way plugging into distance equation is actually the long way. A faster way is to plug the values into
Distance fallen = V initial * t + 1/2(a*t)
We won't need to find V final using another equation.
But anyways, good luck!
Answer:
Explanation:
We are given that
Frequency,f=
Speed,v=40.2 m/s
We have to find the increase in frequency.
We know that
Speed of light,c=
The waves are reflected therefore the change in frequency at the gun is equal to twice the change in frequency.
Therefore, increase in frequency=
A. Increase the distance between the effort and the fulcrum
Answer:
Dr Hutson is the author of several books among them: John Adams and the Diplomacy of the American Revolution (1980); winner of the Gilbert Chinard Prize, 1981; To Make All Laws: The Congress of the United States, 1789-1989 (Washington and Boston, 1989-90; 4th edition, Washington, 1990); The Sister Republics