Answer:
<em>D. remains constant throughout the fall.</em>
Explanation:
<u>Horizontal Launching
</u>
We can launch an object in free air in three forms: vertically, horizontally or inclined. In any case, the only acting force to modify the object's velocity and make it go back to the ground is the force of gravity and it's always directed downwards. Unless friction or air resistance is considered, the horizontal motion is not affected because no force is acting in that direction.
The rock described in the question was launched at 3 m/s pointed horizontally. Immediately after launching, the rock starts to fall to the ground and gain vertical velocity, but the horizontal component remains the same until it completes the flight.
The D option is correct: the horizontal velocity of the rock remains constant throughout the fall
Answer:
a) No
b) No
Explanation:
When a bat is hit in a game of baseball such that it flies out of the field that means it is going with some angle to the horizontal.
a)
Then is such a case the velocity of the ball is never parallel to the acceleration because there acts a net acceleration which is resultant of the acceleration due to the applied force and the acceleration due to gravity but a component of the velocity when the ball descends the height acts parallel to the gravity.
b)
At no point during the motion of the ball its velocity is perpendicular to its acceleration because it has an initial angle of projection form the horizontal.
3rd number line -5- -4 is -9
also it’s math not physics or science
Answer:
Momentum, p = 5 kg-m/s
Explanation:
The magnitude of the momentum of an object is the product of its mass m and speed v i.e.
p = m v
Mass, m = 3 kg
Velocity, v = 1.5 m/s
So, momentum of this object is given by :
p = 4.5 kg-m/s
or
p = 5 kg-m/s
So, the magnitude of momentum is 5 kg-m/s. Hence, this is the required solution.