All categories

3 years ago

If each acute angle of a parallelogram measures 59 degrees, then what is the masure of each obtuse angle?

2 answers:

6 0

There are two acute angles in a parallelogram and 2 obtuse angles. This means that there is <em>360-(59*2) degrees left</em>, or <em>242 degrees left</em> to split between the two obtuse angles. Divide 242 by 2 to get 121 degrees.

:)

xenn [34]3 years ago

5 0

A parallelogram has to have a total of 360 degrees in angles, so we take 59 x 2 to get 118, we then subtract 118 from 360, 360 - 118 = 242, we then divide by two because a parallelogram has 2 obtuse angles, giving us an answer of 121 degrees. Hope this helps

You might be interested in

Admission to the carnival is $10 plus $2 per ride. John spent $38 on admission and

Inessa [10]

Answer:

he went on 14 rides.

Step-by-step explanation:

take your total, 38, subtract that by 10 (because you have to pay the admission fee) and you have 28 dollars spent on rides. each ride costs 2 dollars so divide 28 by 2 and you get 14.

3 0

2 years ago

Read 2 more answers

Does anyone know this ? Thank you

alina1380 [7]

Answer:

Step-by-step explanation:

angle ACB = 180-130=50 degree

angle ABC = 180 - (94+50)

= 180-144

= 36

6 0

3 years ago

Thanks for your response!<br> Question will be show✔

algol13

<h3>Answer:</h3>

$\large\boxed{-1\frac{16}{25},\,\frac{6}{40},\,0.35,\,1\frac{3}{4}}$

<h3>Step-by-step explanation:</h3>

In this question, it's asking you to put the numbers that were given from <em>least </em>to <em>greatest.</em>

Our given numbers are:

$\frac{6}{40}$
0.35
$1\frac{3}{4}$
$-1\frac{16}{25}$

Now, lets sort them out.

We know that negative numbers would be the least. Sicne there's only one negative number, we would put that first because it's the least out of the numbers.

$\frac{6}{40}$ would go next. To make it easier, we can turn it into a decimal. $\frac{6}{40} = 0.15$ when you divide.

0.35 will go next. This would be bigger than 0.15, but lower than the next number.

$1\frac{3}{4}$ would go last, due to the fact that it's the greatest. $1\frac{3}{4}$ is the same as 1.75

When you put them in order, you should get $-1\frac{16}{25},\,\frac{6}{40},\,0.35,\,1\frac{3}{4}$

<h3>I hope this helped you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>

4 0

3 years ago

A 75-gallon tank is filled with brine (water nearly saturated with salt; used as a preservative) holding 11 pounds of salt in so

Debora [2.8K]

Let $A(t)$ = amount of salt (in pounds) in the tank at time $t$ (in minutes). Then $A(0) = 11$ .

Salt flows in at a rate

$\left(0.6\dfrac{\rm lb}{\rm gal}\right) \left(3\dfrac{\rm gal}{\rm min}\right) = \dfrac95 \dfrac{\rm lb}{\rm min}$

and flows out at a rate

$\left(\dfrac{A(t)\,\rm lb}{75\,\rm gal + \left(3\frac{\rm gal}{\rm min} - 3.25\frac{\rm gal}{\rm min}\right)t}\right) \left(3.25\dfrac{\rm gal}{\rm min}\right) = \dfrac{13A(t)}{300-t} \dfrac{\rm lb}{\rm min}$

where 4 quarts = 1 gallon so 13 quarts = 3.25 gallon.

Then the net rate of salt flow is given by the differential equation

$\dfrac{dA}{dt} = \dfrac95 - \dfrac{13A}{300-t}$

which I'll solve with the integrating factor method.

$\dfrac{dA}{dt} + \dfrac{13}{300-t} A = \dfrac95$

$-\dfrac1{(300-t)^{13}} \dfrac{dA}{dt} - \dfrac{13}{(300-t)^{14}} A = -\dfrac9{5(300-t)^{13}}$

$\dfrac d{dt} \left(-\dfrac1{(300-t)^{13}} A\right) = -\dfrac9{5(300-t)^{13}}$

Integrate both sides. By the fundamental theorem of calculus,

$\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac1{(300-t)^{13}} A\bigg|_{t=0} - \frac95 \int_0^t \frac{du}{(300-u)^{13}}$

$\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac{11}{300^{13}} - \frac95 \times \dfrac1{12} \left(\frac1{(300-t)^{12}} - \frac1{300^{12}}\right)$

$\displaystyle -\dfrac1{(300-t)^{13}} A = \dfrac{34}{300^{13}} - \frac3{20}\frac1{(300-t)^{12}}$

$\displaystyle A = \frac3{20} (300-t) - \dfrac{34}{300^{13}}(300-t)^{13}$

$\displaystyle A = 45 \left(1 - \frac t{300}\right) - 34 \left(1 - \frac t{300}\right)^{13}$

After 1 hour = 60 minutes, the tank will contain

$A(60) = 45 \left(1 - \dfrac {60}{300}\right) - 34 \left(1 - \dfrac {60}{300}\right)^{13} = 45\left(\dfrac45\right) - 34 \left(\dfrac45\right)^{13} \approx 34.131$

pounds of salt.

7 0

2 years ago

A cup of raw Arborio rice weighs 7 ounces. One cup will serve 1 people. Arborio rice is purchased in 2-pound boxes for $1.99. Ho

kow [346]

The rice will cost $17.6 for serving 40 people

<h3><u>Solution:</u></h3>

We need to determine the cost of serving 40 people with rice

Arborio rice is purchased in 2-pound boxes for $1.99

The price of 1 pound box will be $\frac{\$ 1.99}{2}=\$ 0.995$

1 Pound (lb) is equal to 16 ounces (oz)

Therefore, the price of 16 ounces is $0.995

A cup of raw Arborio rice weighs 7 ounces and it serve 1 people

$\begin{array}{l}{\text { The cost per person is } \frac{\$ 0.995}{16} \times 7=\$ 0.44} \\\\ {\text { The cost for serving } 40 \text { people }=\$ 0.44 \times 40=\$ 17.6}\end{array}$

Therefore rice will cost $17.6 for serving 40 people

7 0

3 years ago