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professor190 [17]
3 years ago
14

If each acute angle of a parallelogram measures 59 degrees, then what is the masure of each obtuse angle?

Mathematics
2 answers:
hodyreva [135]3 years ago
6 0
There are two acute angles in a parallelogram and 2 obtuse angles. This means that there is <em>360-(59*2) degrees left</em>, or <em>242 degrees left</em> to split between the two obtuse angles. Divide 242 by 2 to get 121 degrees.

:)
xenn [34]3 years ago
5 0
A parallelogram has to have a total of 360 degrees in angles, so we take 59 x 2 to get 118, we then subtract 118 from 360, 360 - 118 =  242, we then divide by two because a parallelogram has 2 obtuse angles, giving us an answer of 121 degrees. Hope this helps
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Jeremy drove 54 miles in 45 minutes.if he drove at a constant rate,what is his speed in miles per hour.
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A) Expand and simplify (4x + 3)(2x - 5)
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8x² - 14x - 15

Step-by-step explanation:

(4x + 3)(2x - 5)

8x² - 20x + 6x - 15

8x² - 14x - 15

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Read 2 more answers
The resting heart rate for an adult horse should average about µ = 47 beats per minute with a (95% of data) range from 19 to 75
KatRina [158]

Answer:

a. 0.0582 = 5.82% probability that the heart rate is less than 25 beats per minute.

b. 0.1762 = 17.62% probability that the heart rate is greater than 60 beats per minute.

c. 0.7656 = 76.56% probability that the heart rate is between 25 and 60 beats per minute

Step-by-step explanation:

Empirical Rule:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean:

\mu = 47

(95% of data) range from 19 to 75 beats per minute.

This means that between 19 and 75, by the Empirical Rule, there are 4 standard deviations. So

4\sigma = 75 - 19

4\sigma = 56

\sigma = \frac{56}{4} = 14

a. What is the probability that the heart rate is less than 25 beats per minute?

This is the p-value of Z when X = 25. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{25 - 47}{14}

Z = -1.57

Z = -1.57 has a p-value of 0.0582.

0.0582 = 5.82% probability that the heart rate is less than 25 beats per minute.

b. What is the probability that the heart rate is greater than 60 beats per minute?

This is 1 subtracted by the p-value of Z when X = 60. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{60 - 47}{14}

Z = 0.93

Z = 0.93 has a p-value of 0.8238.

1 - 0.8238 = 0.1762

0.1762 = 17.62% probability that the heart rate is greater than 60 beats per minute.

c. What is the probability that the heart rate is between 25 and 60 beats per minute?

This is the p-value of Z when X = 60 subtracted by the p-value of Z when X = 25. From the previous two items, we have these two p-values. So

0.8238 - 0.0582 = 0.7656

0.7656 = 76.56% probability that the heart rate is between 25 and 60 beats per minute

3 0
2 years ago
Find three consecutive numbers whose sum equals<br>999.​
mina [271]

Answer:

332, 333, 334

Step-by-step explanation:

First, we acknowledge that the equation that we need to solve will be "x+(x+1)+(x+2)=999" This is because x represents the smallest of three consecutive numbers whose sum is 999. Simplifying this equation will leave us with 3x+3=999 which is simplified further to 3x=996 and again simplified to x=332. X is the smallest number of the three.

4 0
2 years ago
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