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OlgaM077 [116]
2 years ago
15

What happens to the Menu Bar when the object (image, shape, etc.) is "active"?

Computers and Technology
1 answer:
nexus9112 [7]2 years ago
5 0

Answer: Ok so Sorry about this but I will answer thing at 10:20 tommorow I promise

Explanation:

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Guess The Song: <br> What Popping Brand New Whip Just Hopped In, I Got options
Georgia [21]

Answer:

its called whats poppin lol

Explanation:

:)

7 0
2 years ago
In Web design, What kind of tag is referred to as fixed ?<br>​
Tpy6a [65]

Answer:

Most HTML tags are fixed

Explanation:

There are various kind of technology one can use for designing web application. A web designer should know HTML, CSS and other basic building block of web development.

HTML meaning hypertext markup language is used to define the basic structure of a web page . HTML has tags which are used to declare the contents on the web page. The tags includes anchor(<a>), paragraph tag(<p>),header tag(<h1>).

CSS which is known as Cascading style sheet describes the presentation of the web pages.

Other tags in HTML includes <img>, <link>, <ul>  etc and generally this tags are HTML tags which are fixed for a particular kind of job . For example you can't use an image tag <img>   to enclose video instead you use a video tag <video> tag. The header tag <h1> cannot be represented like a paragrapgh tag<p> on the web page. The both of them serve specific purpose and are fixed.  

7 0
2 years ago
It is a JavaScript property used to call a function after a specified time, in milliseconds​
AVprozaik [17]

Answer:

setTimeout is a native JavaScript function (although it can be used with a library such as jQuery, as we'll see later on), which calls a function or executes a code snippet after a specified delay (in milliseconds).

8 0
3 years ago
Read 2 more answers
You want to discard your old computer and want to securely erase the data from your hard drive. What can you use to do this and
qwelly [4]
Go here this should help bunches!
http://www.microsoft.com/security/online-privacy/safely-dispose-computers-and-devices.aspx
Hope this website helps!
5 0
3 years ago
. (a) Prove or disprove carefully and in detail: (i) Θ is transitive and (ii) ω is transitive. (b) Assume n is a positive intege
Sergio [31]

Answer:

The Following are the solution to this question:

Explanation:

In Option a:

In the point (i) \Omega is transitive, which means it converts one action to others object because if \Omega(f(n))=g(n) indicates c.g(n). It's true by definition, that becomes valid. But if \Omega(g(n))=h(n), which implies c.h(n). it's a very essential component. If c.h(n) < = g(n) = f(n) \. They  \Omega(f(n))   will also be h(n).  

In point (ii), The  value of \Theta is convergent since the \Theta(g(n))=f(n). It means they should be dual a and b constant variable, therefore a.g(n) could only be valid for the constant variable, that is  \frac{1}{a}\ \  and\ \ \frac{1}{b}.

In Option b:

In this algorithm, the input size value is equal to 1 object, and the value of  A is a polynomial-time complexity, which is similar to its outcome that is O(n^{2}). It is the outside there will be a loop(i) for n iterations, that is also encoded inside it, the for loop(j), which would be a loop(n^{2}). All internal loops operate on a total number of N^{2} generations and therefore the final time complexity is O(n^{2}).

6 0
3 years ago
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