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oee [108]
2 years ago
13

Figure. ABCD is transformed to A'B'C'D as shown. need help pls

Mathematics
1 answer:
saul85 [17]2 years ago
4 0

Answer:

2nd option

Step-by-step explanation:

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Al and Bill together can complete a work project in 24 days. If Al can do only two-thirds as much as Bill, how long will it take
ella [17]

cccccccccccggggggggggggAnswer:

Step-by-step explanation:

gvvvvvvvvvvvvgggg

4 0
2 years ago
20. If a certain linear function f(x) is evaluated at 0, the answer is 4.
bija089 [108]

Answer:

y = (1/3)x + 4

Step-by-step explanation:

Two points on this line are (0, 4) and (3, 5).

As we move from the first point to the second, x increases by 3 and y increases by 1.  Thus, the slope, m, of the line is m = rise / run = 1/3.

Use the slope-intercept equation:  y = mx + b.

If we use the data from the point (0, 4), we get:

4 = (1/3)(0) + b, so that b = 4.  The desired equation is y = (1/3)x + 4.

7 0
3 years ago
Hacksaw’s Boats of St. Lucia takes tourists on a daily whale/dolphinwatch cruise. Their brochure claims an 80% chance of siting
Fittoniya [83]

Answer:

The probability you see a dolphin or a whale on both days is 0.64

Step-by-step explanation:

Consider the provided information.

It is given that the brochure claims an 80% chance of siting a dolphin or a whale.

The provided claims can be written as: 80% or 0.80

Let say first day you see a dolphin or a whale and same happen on the next day.

Thus, the probability is:

0.80 × 0.80 = 0.64

Probability of see them on both days is 0.64

Hence, the probability you see a dolphin or a whale on both days is 0.64

5 0
3 years ago
A right circular cylinder is inscribed in a sphere with diameter 4cm as shown. If the cylinder is open at both ends, find the la
SOVA2 [1]

Answer:

8\pi\text{ square cm}

Step-by-step explanation:

Since, we know that,

The surface area of a cylinder having both ends in both sides,

S=2\pi rh

Where,

r = radius,

h = height,

Given,

Diameter of the sphere = 4 cm,

So, by using Pythagoras theorem,

4^2 = (2r)^2 + h^2   ( see in the below diagram ),

16 = 4r^2 + h^2

16 - 4r^2 = h^2

\implies h=\sqrt{16-4r^2}

Thus, the surface area of the cylinder,

S=2\pi r(\sqrt{16-4r^2})

Differentiating with respect to r,

\frac{dS}{dr}=2\pi(r\times \frac{1}{2\sqrt{16-4r^2}}\times -8r + \sqrt{16-4r^2})

=2\pi(\frac{-4r^2+16-4r^2}{\sqrt{16-4r^2}})

=2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})

Again differentiating with respect to r,

\frac{d^2S}{dt^2}=2\pi(\frac{\sqrt{16-4r^2}\times -16r + (-8r^2+16)\times \frac{1}{2\sqrt{16-4r^2}}\times -8r}{16-4r^2})

For maximum or minimum,

\frac{dS}{dt}=0

2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})=0

-8r^2 + 16 = 0

8r^2 = 16

r^2 = 2

\implies r = \sqrt{2}

Since, for r = √2,

\frac{d^2S}{dt^2}=negative

Hence, the surface area is maximum if r = √2,

And, maximum surface area,

S = 2\pi (\sqrt{2})(\sqrt{16-8})

=2\pi (\sqrt{2})(\sqrt{8})

=2\pi \sqrt{16}

=8\pi\text{ square cm}

4 0
2 years ago
What’s the area of the rhombus?
miskamm [114]

Answer:

65ft² i guess

Step-by-step explanation:

using area of rombus diagonal=½*d1*d2

4 0
3 years ago
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