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oee [108]
2 years ago
13

Figure. ABCD is transformed to A'B'C'D as shown. need help pls

Mathematics
1 answer:
saul85 [17]2 years ago
4 0

Answer:

2nd option

Step-by-step explanation:

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You have been hired as a marketing consultant to Johannesburg Burger Supply, Inc., and you wish to come up with a unit price for
BartSMP [9]

Answer:

The demabd function is:

q(p)= -4500p+18000

Step-by-step explanation:

The demand follow the linear equation q(p)=mp+b

1. When p=$2.00 and q=9000, the equation is:

9000=m(2.00)+b     (1)

2. Whe p=$4.00 and q=0, the equation is:

0=m(4.00)+b  (2)

3. Solve equation (1) for b:

9000=2m+b\\9000-2m=2m+2m+b\\9000-2m=b

4. Replace the value of b in equation (2)

0=4m+b\\0=4m+9000-2m\\0=2m+9000\\0-9000=2m+9000-9000\\-9000=2m\\\frac{-9000}{2m}=\frac{2m}{2m}\\ -4500=m

The value of m is 4500

5. Calculate b, replacing m:

0=4m+b\\\\0=4(-4500)+b\\0=-18000+b\\18000=b

The value of b is 18000

3 0
3 years ago
Write a polynomial that represents the area of the shaded region
marusya05 [52]
<h3>Answer: x^2-3x+36</h3>

=========================================

Explanation:

The larger rectangle has area of (x+1)(x+1) = x^2+2x+1 through the use of the FOIL rule or distribution

If you use distribution, then it might help to let y = x+1 so we'd have y(x+1) lead to xy+1y which becomes x(x+1)+1(x+1). From there it might be easier to see how to get x^2+2x+1 after everything distributes again and simplifies.

The smaller rectangle has area 5x-35 which is found by distributing 5(x-7)

To get the shaded area, we subtract the two rectangle areas found above

shaded area = (larger area) - (smaller area)

shaded area = (x^2+2x+1) - (5x - 35)

shaded area = x^2+2x+1 - 5x + 35

shaded area = x^2-3x+36

6 0
3 years ago
The equation P=6s represents the perimeter P of a regular hexagon with side length s. What is the perimeter of a regular hexagon
Verdich [7]

we know that s = 3, so plug it in.

P = 6(3)

P = 18

perimeter = 18 km

6 0
3 years ago
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Yolanda was gone for 12 hours 
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Anybody know the answer for this?
Ne4ueva [31]
A. 

You can subtract values that are being divided in Sin waves. 
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