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Darina [25.2K]
3 years ago
10

Someone fires a slingshot at a target that is far enough away to take 1.4 seconds to reach. How far below does the target does t

he slingshot pellet hit?
Physics
1 answer:
Korolek [52]3 years ago
6 0
There is not enough information to answer the question
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The motion of a car on a position-time graph is represented with a horizontal line. What does this indicate about the car's moti
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Definition: A potential path for the flow of electricity with at least one gap in the path that prevents this flow. The gap is u
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Open circuit

Explanation:

An open circuit is simply an electrical circuit that is not complete. In such a circuit, there is a gap and this will not allow the electric current to pass through.

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In such a circuit, the wires are cut of and not connected properly.

The reverse is a closed circuit.

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What is nuclear energy
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Nuclear energy <em>is t</em><span><em>he energy released during nuclear fission or fusion.

</em>
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What can a machine do?
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The width of the central maximum is defined as the distance between the two minima closest to the center of the diffraction patt
Gnom [1K]

Answer:

The value of the angle is \bf{ \sin^{-1}[h/am_{e}v]}.

Explanation:

Given:

The condition for diffraction minima is

a \sin \theta = m \lambda~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(1)

where, a is the slit-width, \theta is the angle of incidence, m is the order number and \lambda is the wavelength of the light.

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According to de Broglie's hypothesis

\lambda &=& \dfrac{h}{p}\\               &=& \dfrac{h}{m_{e}v}

Here, h is Planck's constant, m_{e} is the mass of the electron and v is the velocity of the electron.

For first minimum m = 1.

From equation (1), we have

&& a \sin \theta = \dfrac{h}{m_{e}v}\\&or,& \theta = \sin^{-1}[\dfrac{h}{am_{e}v}]

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3 years ago
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