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3 years ago

Calculate the momentum of a photon of light that has a frequency of 5.09 x 10^14 HZ.

Physics

1 answer:

Deffense [45]3 years ago

7 0

Answer:

Momentum of a photon, $P=1.13\times 10^{-27}\ kg-m/s$

Explanation:

It is given that,

The frequency of light, $f=5.09\times 10^{14}\ Hz$

We need to find the momentum of a photon. The relation between momentum and wavelength is given by :

$P=\dfrac{h}{\lambda}$

Since, $\lambda=\dfrac{c}{f}$

$P=\dfrac{fh}{c}$ , c is the speed of light

$P=\dfrac{5.09\times 10^{14}\times 6.67\times 10^{-34}}{3\times 10^8}$

$P=1.13\times 10^{-27}\ kg-m/s$

So, the momentum of a photon is $1.13\times 10^{-27}\ kg-m/s$ . Hence, this is the required solution.

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4 years ago

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Well, there are different ways you can represent the motion
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4 years ago

Read 2 more answers

A wire of length 6cm makes an angle of 20° with a 3 mT

Crazy boy [7]

Answer:

Approximately $7.3 \times 10^{-3}\; \rm A$ (approximately $7.3\; \rm mA$ ) assuming that the magnetic field and the wire are both horizontal.

Explanation:

Let $\theta$ denote the angle between the wire and the magnetic field.

Let $B$ denote the magnitude of the magnetic field.

Let $l$ denote the length of the wire.

Let $I$ denote the current in this wire.

The magnetic force on the wire would be:

$F = B \cdot l \cdot I \cdot \sin(\theta)$ .

Because of the $\sin(\theta)$ term, the magnetic force on the wire is maximized when the wire is perpendicular to the magnetic field (such that the angle between them is $90^\circ$ .)

In this question:

$\theta = 20^\circ$ (or, equivalently, $(\pi / 9)$ radians, if the calculator is in radian mode.)
$B = 3\; \rm mT = 3 \times 10^{-3}\; \rm T$ .
$l = 6\; \rm cm = 6 \times 10^{-2}\;\rm m$ .
$F = 1.5\times 10^{-4}\; \rm N$ .

Rearrange the equation $F = l \cdot I \cdot \sin(\theta)$ to find an expression for $I$ , the current in this wire.

$\begin{aligned} I &= \frac{F}{l \cdot \sin(\theta)} \\ &= \frac{3\times 10^{-3}\; \rm T}{6 \times 10^{-2}\; \rm m \times \sin \left(20^{\circ}\right)} \\ &\approx 7.3 \times 10^{-3}\; \rm A = 7.3 \; \rm mA\end{aligned}$ .

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3 years ago

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