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Firlakuza [10]
3 years ago
7

to keep everything the same between the man and the boy, the table below for the mans motion covers the same interval as the one

you've already analyzed for the boy. now enter the mans velocity for these 2 times and then calculate his change in velocity and average acceleration during the time interval
Physics
1 answer:
mixer [17]3 years ago
5 0

Answer:

I hope this helps

Explanation:

i had to submit just to get the answer,Have a great day!!!

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High-energy particles are observed in laboratories by photographing the tracks they leave in certain detectors; the length of th
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3 years ago
An electron and a second particle both move in circles perpendicular to a uniformmagnetic field. The mass of the second particle
Katarina [22]

Answer:

The change on the second particle is 2.93\times 10^{-16}\ C.

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T=\dfrac{2\pi m}{Bq}

It is given that the magnetic field is uniform. The mass of the second particle is the same as that of a proton but thecharge of this particle is different from that of a proton.

m_s=m_p

If both particles take the same amount of time to go once around their respective circles. So,

T_e=T_s\\\\\dfrac{2\pi m_e}{Bq_e}=\dfrac{2\pi m_s}{Bq_s}\\\\\dfrac{m_e}{q_e}=\dfrac{m_p}{q_s}\\\\q_s=\dfrac{m_pq_e}{m_e}\\\\q_s=\dfrac{1.67\times 10^{-27}\times 1.6\times 10^{-19}}{9.11\times 10^{-31}}\\\\q_s=2.93\times 10^{-16}\ C

So, the change on the second particle is 2.93\times 10^{-16}\ C.

7 0
3 years ago
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