to keep everything the same between the man and the boy, the table below for the mans motion covers the same interval as the one
1 answer:
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The electric field produced by a large flat plate with uniform charge density on its surface can be found by using Gauss law, and it is equal to
where
is the charge density
is the vacuum permittivity
We see that the intensity of the electric field does not depend on the distance from the plate. Therefore, the strenght of the electric field at 4 cm from the plate is equal to the strength of the electric field at 2 cm from the plate:
where
We see that the intensity of the electric field does not depend on the distance from the plate. Therefore, the strenght of the electric field at 4 cm from the plate is equal to the strength of the electric field at 2 cm from the plate:
Answer:
1.44 x 10⁻⁶ C
Explanation:
= charge on one sphere
= charge on other sphere
= Total charge on the two spheres = 40 μC
=
= 40 x 10⁻⁶
= (40 x 10⁻⁶) -
eq-1
= distance between the two spheres = 50 cm = 0.50 m
= magnitude of force between the two spheres = 2.0 N
Magnitude of force between the two spheres is given as
= 1.44 x 10⁻⁶ C
Answer and explanation:
A correct option is an option (B).
The electrical force between two charges is given as,
The electrical force is directly proportional to the product of two charges. Thus Force will depend on two charges irrespective of their signs.
Option (A) is incorrect because if charges are opposite, the value of force will not be zero. It will be -ve.
Option (C) is incorrect because the force is directly proportional to the product of charges, it depends on the amount of charge.
Option (D) is also incorrect because the force in inversly proportional to the distance between two charges. Thus, if the distance between two charges is increased, the force between two charges will decrease.
Concllusion:
The correct option is option (B).