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Firlakuza [10]
3 years ago
7

to keep everything the same between the man and the boy, the table below for the mans motion covers the same interval as the one

you've already analyzed for the boy. now enter the mans velocity for these 2 times and then calculate his change in velocity and average acceleration during the time interval
Physics
1 answer:
mixer [17]3 years ago
5 0

Answer:

I hope this helps

Explanation:

i had to submit just to get the answer,Have a great day!!!

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Amy has a mass of 30 kg, and she is riding a skateboard traveling 5 m/s. What is her momentum?
Flauer [41]
Hey there!

So we know that m*v=P.
And in this question m=30
v=5 m/s
P = 30*5 Kgm/s
P = 150 Kgm/s

So, your final answer is 150 Kg.m/s

Hope this helps! :)
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3 years ago
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True or false materials that are poor conductors are poor insulaters
prohojiy [21]
False, rubber is a poor conductor but is a good insulator.
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4 years ago
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Does the zero electric field intensity in a given region imply zero potential?​
Rama09 [41]

Answer:

No, just because the electric field is zero at a particular point, it does not necessarily mean that the electric potential is zero at that point. ... At the midpoint between the charges, the electric field due to the charges is zero, but the electric potential due to the charges at that same point is non-zero.

Explanation:

7 0
3 years ago
A person uses 750 kcal on a long walk calculate the energy used for the walk in kilojoules
guapka [62]
Basically, this problem asks you to convert kilocalories (kcal) to kilojoules (kJ). Both are units of energy. To convert kcal to kJ, the equivalence is: 1 kcal = 4.184 kJ. Through dimensional analysis, the solution is as follows:

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6 0
4 years ago
A projectile is launched upward at an angle of 70⁰ from the horizontal and strikes the ground a certain distance down range. For
OLga [1]

Answer:20°

Explanation:

Recall

Range R of a projectile is given by U^2sin2A/g

We're U = velocity,A= angle of projection and g is acceleration due to gravity

From the question the range R are the same

Hence R1=R2

U1^2sin2A/g=U2^2sin2B/g

But U1=U2 and g=g

Hence sin2A=sin 2B

Sin 2*70= sin2*B

0.6427=sin2B

B=sin inverse(0.6427)=40/2=20°

7 0
3 years ago
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