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3 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Mathematics

1 answer:

raketka [301]3 years ago

5 0

Answer:

the answer is 87 keep trying also the answer 45 aha tricked you

Step-by-step explanation:

um not sure of the answer but loo-kit u p on o just keep trying quay

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Tell me w what is the book and notebook

Oduvanchick [21]

Answer:

a book is something you read a notebook is something you write in.

Step-by-step explanation:

7 0

2 years ago

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Is my solution correct?

nlexa [21]

Hello there!

Yes, your solution is correct! A way to check it is replacing the value you found for x into x in the equation.

3(2-x) = 7 - 4x ⇒ 3(2-1) = 7 - 4(1)

And now solve 3(2-1) = 7 - 4(1).

3(1) = 7 - 4(1)

3 = 7 - 4

3 = 3

Since it is a true statement that 3 is equal to 3, it means your solution of x = 1 is correct. Good job! :)

8 0

3 years ago

Read 2 more answers

Which equation has the solutions x = -3 ± √3i/2 ?

Maurinko [17]

Answer:Answer is option C : [ $x^{2}$ + 3x + 3 ] =0

Note: None of options matches with given question.

instead of "-3" , there should be "- $\frac{3}{2}$ ".

Step-by-step explanation:

Note: None of options matches with given question.

instead of "-3" , there should be " $\frac{3}{2}$ ".

Here, First thing you have to observe the nature of roots.

∴ x = - $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i and x = - $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$

∴ [ x+( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i) ][ x+( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ]=0

∴ [ $x^{2}$ + x( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i)+ x( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i) + ( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i)( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ]=0

∴ [ $x^{2}$ + $\frac{3}{2}$ x + $\frac{\sqrt{3}}{2}$ ix + $\frac{3}{2}$ x - $\frac{\sqrt{3}}{2}$ ix + (3- $\frac{\sqrt{3}}{2}$ i)(3+ $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + ( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i)( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ - ( $\frac{\sqrt{3}}{2}$ i)( $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ - ( $\frac{3}{4}$ ) $i^{2}$ ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ + ( $\frac{3}{4}$ ) ] =0

∴ [ $x^{2}$ + 3x + $\frac{12}{4}$ ] =0

∴ [ $x^{2}$ + 3x + 3 ] =0

Thus, Answer is option C : <em>[ $x^{2}$ + 3x + 3 ] =0 </em>

6 0

3 years ago

Norma earns $22 per hour. She donates 5% of her wages to her favorite charity. If she wants to have at least $748 left after her

enyata [817]

I did the math on a calculator and i got C 36.

7 0

3 years ago

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Plss help me as soon as possible i will give you lots of points

mezya [45]

Answer:

Step-by-step explanation:

75x + -300 = 25x + 200

Reorder the terms:

-300 + 75x = 25x + 200

Reorder the terms:

-300 + 75x = 200 + 25x

Solving

-300 + 75x = 200 + 25x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-25x' to each side of the equation.

-300 + 75x + -25x = 200 + 25x + -25x

Combine like terms: 75x + -25x = 50x

-300 + 50x = 200 + 25x + -25x

Combine like terms: 25x + -25x = 0

-300 + 50x = 200 + 0

-300 + 50x = 200

Add '300' to each side of the equation.

-300 + 300 + 50x = 200 + 300

Combine like terms: -300 + 300 = 0

0 + 50x = 200 + 300

50x = 200 + 300

Combine like terms: 200 + 300 = 500

50x = 500

Divide each side by '50'.

x = 10

Simplifying

x = 10

3 0

3 years ago