1)√3 = 1.73 (near +2 left)
2)√10 = 3+something (near +3, towards RHS)
3)√26 = 5+something (near +5, towards RHS)
4)-√5 = -2-something (near -2 towards left)
5)-√14 = -4+something (near -4 towards right)
Answer:
11 /13 = t
Step-by-step explanation:
5/13 = t -6/13
Add 6/13 to each side
5/13 + 6/13 = t -6/13+ 6/13
11 /13 = t
Two triangle are congruent when the shape and size of both the triangle are same. The given information is the SAS case.
To find the form of the case we need to know about the triangle congruence theorem.
<h3>What is triangle congruence theorem?</h3>
Two triangle are congruent when the shape and size of both the triangle are same.
Triangle congruence theorem are-
- Angle-Side-Angle theorem (AAS)- This theorem states that two triangle is congruent when two angle and one side of the triangle are respectively equal to the two angles and same side of the other triangle.
- Side-Side-Side theorem (SSS)- When the three sides of the one triangle is equal to the three sides of the other triangle respectively, then the triangle are congruent.
- Side-Angle-Side theorem (SAS)- Two sides and the included angle of are equal to the two sides and one angle of other triangle respectively.
Given information-
Evelyn is 104 meters from the take off.
The angle of elevation of the plane is 12°.
The plane is 100 meters away from the takeoff point.
The distance is 100 meters and 104 meters. The other two sides , as are same and the angle of elevation is also same for this case (12 degrees).
Thus the two triangle formed which are congruent.
As above discussed the case of SAS exists for the triangle congruence theorem.
Hence the given information is the SAS case.
Learn more about the triangle congruence theorem here;
brainly.com/question/19258025
Answer:
Explain the circumstances for which the interquartile range is the preferred measure of dispersion
Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.
What is an advantage that the standard deviation has over the interquartile range?
The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.
Step-by-step explanation:
Previous concepts
The interquartile range is defined as the difference between the upper quartile and the first quartile and is a measure of dispersion for a dataset.
The standard deviation is a measure of dispersion obatined from the sample variance and is given by:
Solution to the problem
Explain the circumstances for which the interquartile range is the preferred measure of dispersion
Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.
What is an advantage that the standard deviation has over the interquartile range?
The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.
I believe the answer is D
if you fold it all together using the dotted line, it looks that it will all fit together and look like the above shape
hope this helps
