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Natasha_Volkova [10]
2 years ago
9

The 95% confidence interval is from __ to __?

Mathematics
2 answers:
Nadya [2.5K]2 years ago
7 0

Answer:

The 95% confidence interval is from 0.5 to 0.027?

Step-by-step explanation: hope that helps :)

ra1l [238]2 years ago
6 0

Answer:

The 95% confidence interval is from 00.19 to 0.6?

You might be interested in
3/5 + 1/2 =? ; 1/2 + 3/8 =? ; 1/2 + 2/5=?
slavikrds [6]
3/5+1/2=___
To add them together, convert both fractions so they have the same denominator.
3/5=6/10 and 1/2=5/10
6/10+5/10=11/10, or 1 1/10

1/2+3/8=___
Same for this one- convert both fractions so they have the same denominator.
1/2=4/8 and 3/8 stays the same
4/8+3/8=7/8

1/2+2/5
And again, convert both fractions so they have the same denominator.
1/2=5/10 and 2/5= 4/10
5/10+4/10=9/10

Hope this helps :-)
5 0
3 years ago
Read 2 more answers
Please show your work please
Nadusha1986 [10]
The correct answer is 4. 
5 0
3 years ago
What is the answer to the problem
Tanya [424]

Answer:

a - 8

b - 20

c - 40

answer - 40% of 20 is 8

Step-by-step explanation:

20 x .4 = 8

.4 is found by the 40 / 100

8 0
3 years ago
Read 2 more answers
Please help<br><br><br><br> ..........................
Alenkinab [10]

Answer:

9/2

Step-by-step explanation:

perpendicular lines have slopes that are opposite and reciprocal

the reciprocal of -2/9 is 9/2

7 0
2 years ago
The sum of two integers is 26. the sum of the squares of the two integers is 340. what is the product of the two numbers?
Phoenix [80]
Lets say that the two unknown integers are n and m.

We know the following things about n and m:

n+m=26
n^2+m^2=340

And, we want to find nm.

To solve this, we'll use the expansion of the squared of the sum of any two inegers; this is expressed as:

(n+m)^2=n^2+2nm+m^2

So, given what we know about the unknown integers, the previous can be written as:

(26)^2=340+2nm

We can easily solve for nm:

nm= \frac{(26)^2-340}{2}= \frac{676-340}{2}= \frac{336}{2}=168

The answer is 168.

Another approach to solve the problem is, from the two starting equations, compute the values of n and m, which are 12 and 14, and directly compute their product; however, the approach described is more elegant. 
5 0
3 years ago
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