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bagirrra123 [75]
3 years ago
13

2) A car starting from ret accelerate uniformly A and attain a speed of soms to 30seconds. It maintains t in steady speed for an

other 30 Seconds-It then slows de Unsformly until it comes to rest is the next 40 secor graph for the moties gloph determine; tine a) sketch the velouty 6 from the Its acceleration Decceleration 1. 11) The total distance covered by the car​
Physics
1 answer:
Klio2033 [76]3 years ago
6 0

Answer:

tttmmggmfmfmfmfmfmfmfmgmgmtmtmtmtmtm

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The following number - 0.050437 - written to TWO significant figures would be
Sophie [7]

Answer:

0.050000

Explanation:

your welcome :)

7 0
3 years ago
Suppose you apply a flame and heat one liter of water, raising its temperature 10°C. If you transfer the same heat energy to two
polet [3.4K]
(a) the water density is d=1000 kg/m^3, and 1 liter corresponds to a volume of V=1 L=0.001 m^3. Therefore we can find the mass of the water in the first case:
m=dV=(1000 kg/m^3)(0.001 m^3)=1 kg

The amount of heat supplied to the water to raise its temperature by \Delta T=10 ^{\circ} C is
Q=m C_s \Delta T (1)
where 
C_s = 4.18 kJ/(kg ^{\circ} C} is the specific heat capacity of the water. 
Using the data, we find
Q=(1 kg)(4.18 kJ/(kg ^{\circ} C)(10^{\circ} C)=41.8 kJ

We want to find the increase in temperature if we transfer the same amount of heat Q to 2 liters of water. The mass of 2 liters of water is
m=dV=(1000 kg/m^3)(0.002 m^3)=2 kg
And so by re-arranging equation (1) we can calculate the new increase of temperature:
\Delta T_2 =  \frac{Q}{m C_s}  =  \frac{41.8 kJ}{(2 kg)(4.18 kJ/(kg ^{\circ} C)}=5 ^{\circ} C

(b) Now we have 3 liters of water. SImilarly to point (a), the mass is now
m=dV=(1000 kg/m^3)(0.003 m^3)=3 kg
And so, the increase in temperature if we use the same amount of heat as before is
\Delta T_3= \frac{Q}{m C_s} = \frac{41.8 kJ}{(3 kg)(4.18 kJ/(kg ^{\circ} C)}=3.3 ^{\circ} C
5 0
3 years ago
Who has greater displacement, an astronaut who has just completed an orbit of the earth or you when you have just traveled from
Arte-miy333 [17]

Answer:

Explanation:

This is going to sound like an absurd answer, but sometimes physics can be a little strange.

This answer is weird because of the definition of displacement. It means the distance from the starting point to the ending point, disregarding what happened in between. The point is that the astronaut is at the starting point of his orbit. By definition the starting and ending points are the same. His displacement is 0.

So the answer is you have the greater displacement when you walked one way to school.  The starting point and the ending point are different. You have gone further.

However just to make things a little nasty, when you walk home again, your displacement will be the same as the astronaut's -- 0 meters because you will be right back where you started from.

7 0
3 years ago
(50 POINTS) Set the ball and the barrier about two feet apart on the table. Grasp both ends of the ruler. Push the ball using th
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bounces off barrier back to rluler ....

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Where does a magnetic field occur in relation to an electrified wire?
bekas [8.4K]

Answer:

Around the entire length of the wire

Explanation:

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