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Nataliya [291]
3 years ago
9

A student makes the following claim:

Physics
1 answer:
Trava [24]3 years ago
4 0

Answer:

A, C, E

Explanation:

I put this and got it right.

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If a 126 gram marble rolls down a hill at an acceleration of 3.0m/s2, what would the force be on the marble?​
adelina 88 [10]

Answer:

Explanation:

Net force would be the one causing the acceleration or

F = ma = 0.126(3.0) = 0.378 N

4 0
3 years ago
A gymnast of mass 70.0 kgkg hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume
n200080 [17]

Answer:

43994

Explanation:

Hope this helps!

7 0
4 years ago
Three noise sources produce volume (loudness) levels of 70, 73, and 80 dB when acting separately. When the sources act together,
Mashutka [201]

Sound at 70 dB is 70 dB louder than the human reference level.  That's 10⁷ times as much as the reference sound power.

Sound at 73 dB is 73 dB louder than the human reference level.  That's 10⁷.³  or  2 x 10⁷  times as much as the reference sound power.

Sound at 80 dB is 80 dB louder than the human reference level.  That's 10⁸  or 10 x 10⁷ times as much as the reference sound power.

Now we can adumup:

Intensity of all 3 sources = (10⁷) + (2 x 10⁷) + (10 x 10⁷)

Intensity = (13 x 10⁷) times the sound power reference intensity.

Intensity in dB = 10 log (13 x 10⁷) = 10 (7 + log(13)

Intensity = 70 + 10 log(13)

Intensity = 70 + 10 (1.114)

Intensity = 70 + 11.14

Intensity = <em>81.14 dB</em>

<em>______________________________________</em>

Looking at the questioner's profile, I seriously wonder whether I'll ever get a comment in return from this creature, and how I'll ever find out if my solution is correct.  For that matter, I'm also seriously questioning how and whether my solution will ever be used for anything.

8 0
3 years ago
A proton starting from rest travels through a potential of 1.0 kV and then moves into a uniform 0.040-T magnetic field directed
Hatshy [7]

Answer:

0.114m

Explanation:

From the general expression for the radius of the proton's resulting orbit, we have

r=\frac{mv}{qB}

where q is is the charge of the proton 1.6*10^{-19}C

m is the mass of the proton  1.67*10^{-27}kg

B is the magnetic field  0.040T

and v i the speed.

to determine the speed, we use the expression

Kinetic Energy=qV

1/2mv^{2}=qV

where <em>V  </em>is the voltage value i.e 1.0kv

and v is the speed

Hence, from simple rearrangement we have the speed v to be

v=\sqrt{\frac{2Vq}{m}} \\

if we substitute value, we have

v=\sqrt{\frac{2*1000*1.6*10^{-19} }{1.67*10^{-27}}} \\

carrying out careful arithmetic we arrive at

v=4.38*10^{5} m/s.

using the value for the speed in the expression for the radius of the orbit as stated earlier, we have

r=\frac{1.67*10^{-27}*4.38*10^{5}}{1.6*10^{-19}*0.04} \\

r=0.114m

7 0
3 years ago
A car that increases its speed from 20 km/h to 100 km/h undergoes
Kamila [148]

Answer:

accelaration

Explanation:

3 0
3 years ago
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