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ivolga24 [154]
3 years ago
11

Use point-slope form to write the equation of a line that passes through the point

Mathematics
2 answers:
nalin [4]3 years ago
8 0

Answer:

Step-by-step explanation:

Point slope form: y - y1 = m(x -x1)

y - [-16] = \dfrac{1}{2}(x - [-3] )\\\\y + 16 = \dfrac{1}{2}(x + 3)\\\\\\y + 16 = \dfrac{1}{2}x + \dfrac{3}{2}\\\\y =\dfrac{1}{2}x+\dfrac{3}{2}-16\\\\y=\dfrac{1}{2}x +\dfrac{3}{2}-\dfrac{32}{2}\\\\\\y=\dfrac{1}{2}x  - \dfrac{29}{2}

Furkat [3]3 years ago
7 0

Answer:

y= -\frac12 x +\frac{29}2

Step-by-step explanation:

Let's start with the point- slope form:

y-y_0=m(x-x_0)

and replace the values we have

y-(-16) = -\frac12 (x-(-3))

We're almost there, we just need to write it in a better looking form.

y+16= -\frac12 (x+3)\\y=-\frac12 x - \frac32 + \frac{32}2\\y= -\frac12 x +\frac{29}2

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Answer:

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Step-by-step explanation:

From the figure we can infer that our triangle has vertices A = (-5, 4), B = (1, 4), and C = (3, -4).

First thing we are doing is find the lengths of AB, BC, and AC using the distance formula:

d=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}

where

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