Question

Use point-slope form to write the equation of a line that passes through the point

Answer 1

Answer:

Step-by-step explanation:

Point slope form: y - y1 = m(x -x1)

$y - [-16] = \dfrac{1}{2}(x - [-3] )\\\\y + 16 = \dfrac{1}{2}(x + 3)\\\\\\y + 16 = \dfrac{1}{2}x + \dfrac{3}{2}\\\\y =\dfrac{1}{2}x+\dfrac{3}{2}-16\\\\y=\dfrac{1}{2}x +\dfrac{3}{2}-\dfrac{32}{2}\\\\\\y=\dfrac{1}{2}x - \dfrac{29}{2}$

Answer 2

Answer:

$y= -\frac12 x +\frac{29}2$

Step-by-step explanation:

Let's start with the point- slope form:

$y-y_0=m(x-x_0)$

and replace the values we have

$y-(-16) = -\frac12 (x-(-3))$

We're almost there, we just need to write it in a better looking form.

$y+16= -\frac12 (x+3)\\y=-\frac12 x - \frac32 + \frac{32}2\\y= -\frac12 x +\frac{29}2$