Pls pls pls help help pls

Mathematics

2 answers:

pav-90 [236]2 years ago

5 0

Answer:

b or 7/9

Step-by-step explanation:

SSSSS [86.1K]2 years ago

3 0

Answer:

The correct answer is B: 7/9

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The perimeter of a triangle is 7 m. The longest side is twice the length of the shortest side. The sum of the

34kurt

Answer:

See below in bold.

Step-by-step explanation:

Let the length of the shortest side be x, then the longest side = 2x.

Also x + y = 2x + 1 where y = length of the middle side,

Simplifying:

2x - x - y = -1

x - y = -1 (A)

Also as the perimeter = 7:

x + 2x + y = 7

3x + y = 7 (B)

Adding (A) and (B):

4x + 0 = 6

x = 6/4 = 1.5

Plug x = 1.5 into equation B:

3(1.5) + y = 7

y = 7 - 4.5 = 2.5.

Answer:

So the shortest side = 1.5, middle = 2.5 and longest = 2*1.5 = 3.

3 0

2 years ago

Suppose that you need to create a list of n values that have a specific known mean. Some of the n values can be freely selected.

Leno4ka [110]

As the problem indicates, degrees of freedom are the number of values that can be independently selected before it is necessary to choose specific values to arrive at the desired result.

The average, on the other hand, results from the sum of a list of values divided by the amount of values in the summed list.

Assume that the mean sought is $x$ and consider that the list is composed of a single element $a$ , in that case no random number can be selected, since the mean $x$ must correspond to that number.

If the list were composed of two elements $a$ and $b$ , one of the two values could be chosen randomly, and according to the chosen value the second should be the one whose sum with the previous one results in $2x$ , this given that the formula of the average $\sum\limits_{i=1}^n \frac{ x_{i}}{n}$ .

With three values $a$ , $b$ and $c$ , it is possible to select two freely, since the thirteen must be the one that balances the sum of $a+b$ , that is $(a + b) + c = 3x$ .

Thus, in general, with n values, it is possible to select $n-1$ values freely whose sum must be balanced by the last value so that the whole sum is $nx$ .