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Svet_ta [14]
3 years ago
14

Pls pls pls help help pls

Mathematics
2 answers:
pav-90 [236]3 years ago
5 0

Answer:

b or 7/9

Step-by-step explanation:

SSSSS [86.1K]3 years ago
3 0

Answer:

The correct answer is B: 7/9

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What is the diameter of a sphere with a volume of 498 in3, to the nearest tenth of an inch
Romashka-Z-Leto [24]

Answer:

9.8 inches

Step-by-step explanation:

<h3>Formula for volume of the sphere is = 4/3πr³</h3><h3>Form and solve the equation for the radius</h3><h3>So: 4/3πr³= 498in³</h3><h3>πr³= 498in³*3/4 which = to 373.5in³</h3><h3>r³= 373.5in³/π</h3><h3>r=∛(373.5in³/π)</h3><h3>calculate r and times the result by 2 for diameter</h3><h3>it will be 9.834...</h3><h3>nearest tenth of an inch means the accuracy is 1 decimal place because nearest tenth= 1/10 or 0.1</h3><h3>So the final answer is 9.8in</h3>
3 0
4 years ago
3x-50 (7x) find the value of x
Naya [18.7K]

x=23

Simplifying

(3x + -50) + (7x)

Reorder the terms:

(-50 + 3x) + (7x)

Remove parenthesis around (-50 + 3x)

-50 + 3x + (7x) =

Combine like terms: 3x + (7x)

-50 + 10x

Solving

-50 + 10x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '50' to each side of the equation.

-50 + 50 + 10x = 180 + 50

Combine like terms: -50 + 50 = 0

0 + 10x = 180 + 50

10x = 180 + 50

Combine like terms: 180 + 50 = 230

10x = 230

Divide each side by '10'.

Simplifying

x = 23

8 0
3 years ago
find the length of the base of a square pyramid if the volume is 1,024 cubic inches and has a height of 12 inches
Tju [1.3M]
Let 's x the length of the pyramid:
V=x²*h/3
V=1024 and h=12
So x²*12/3=1024
==>x²=1024*3/12
==>x²=256
==>x²=16²
==> x=16 for (x=-16 must be exclude <0)

......brainpower pts pls
7 0
3 years ago
Read 2 more answers
I do not understand how to do this problem please help!
kicyunya [14]
Y=-4/3x+300 hope this helps
4 0
4 years ago
Read 2 more answers
If y=7.2 and r= 1.1 have been rounded to 1 decimal place find the possible value of y x r
Shkiper50 [21]

Answer:

the \:  possible  \: value  \: of \: ( y  \times  r) = 7 \times 1 = \boxed{ 7} \\ or \\   ( 7.2  \times  1.1) =  \boxed{ 7.9} \\

7 0
3 years ago
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