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3 years ago

Can someone help me with this

Mathematics

2 answers:

Kisachek [45]3 years ago

7 0

Answer:

2, 4, 6, and 8, respectively

Step-by-step explanation:

The rule says that 2 times the x value, which we are given, equals to y, which we must find. So all we hve to do is multiply each of the given x values by two to get the y value.

kkurt [141]3 years ago

5 0

Answer:

y=2x

Step-by-step explanation:'

Multiply the x times 2

$\frac{1}{2}$ $\frac{2}{4}$ $\frac{3}{6}$ $\frac{4}{8}$

2 4 6 8

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Scilla [17]

Answer:

£1.62

Step-by-step explanation:

add them all up then subtract 100 and forget about the negative sign

3 0

3 years ago

If T is the midpoint of CE then CT=TE

mr_godi [17]

Answer: true statement

6 0

4 years ago

The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha

Xelga [282]

Answer:

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

Step-by-step explanation:

Let suppose that function $f$ is continuous and integrable in the given intervals, by integral definition of average we have that:

$\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6$ (1)

$\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20$ (2)

By Fundamental Theorems of Calculus we expand both expressions:

$\frac{F(3)-F(-2)}{3-(-2)} = -6$

$F(3) - F(-2) = -30$ (1b)

$\frac{F(5)-F(3)}{5-3} = 20$

$F(5) - F(3) = 40$ (2b)

We obtain the average value of $f$ over the interval $[-2, 5]$ by algebraic handling:

$F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)$

$F(5) - F(-2) = 10$

$\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}$

$\bar f = \frac{10}{7}$

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

4 0

3 years ago

Write the equation of the line in fully simplified slope-intercept form.

Lina20 [59]

Answer:

$y=-6x+2$

Step-by-step explanation:

Hi there!

Slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when x=0)

1) Determine the slope (m)

$m=\displaystyle \frac{y_2-y_1}{x_2-x_1}$ where two points that fall on the line are $(x_1,y_1)$ and $(x_2,y_2)$

Given the graph, we determine which points we could use. For example, we could use the two points $(0,2)$ and $(1,-4)$ :

$m=\displaystyle \frac{-4-2}{1-0}\\\\m=\displaystyle \frac{-6}{1}\\\\m=-6$

Therefore, the slope of the line is -6. Plug this into $y=mx+b$ :

$y=-6x+b$

2) Determine the y-intercept (b)

Recall that the y-intercept occurs when x=0. Given the point (0,2), we know that the y-intercept is 2. Plug this into $y=-6x+b$ :

$y=-6x+2$

I hope this helps!

5 0

3 years ago

(x-4)/(2x+1)-3 can you help me with this question

lilavasa [31]

Answer:

$\frac{(x - 4)}{(2x + 1)} - 3$ $=$ $\frac{-7x- 7}{3x + 1}$

Step-by-step explanation:

Given

$\frac{(x - 4)}{(2x + 1)} - 3$

Required

Solve

Express 3 as a fraction

$\frac{(x - 4)}{(2x + 1)} - \frac{3}{1}$

Take LCM

$\frac{x - 4 - 3(2x + 1)}{3x + 1}$

$\frac{x - 4 - 6x - 3}{3x + 1}$

Collect Like Terms

$\frac{x - 6x- 4 - 3}{3x + 1}$

Simplify like terms

$\frac{-7x- 7}{3x + 1}$

Hence:

$\frac{(x - 4)}{(2x + 1)} - 3$ $=$ $\frac{-7x- 7}{3x + 1}$

4 0

3 years ago