Well, let's say the numbers are "a" and "b"
so a * b = ab
ok... now, if we reduce "a" by 25%, that means the new size is just 75% of the old one, how much is 75% of a? well, (75/100) * a, or 0.75a
now let's reduce "b" by 50%, that means the new size is 50% or half, how much is 50% of b? well (50/100)*b, or 0.5b

now, the new size of "ab" is just 0.375ab... well, let's revert the decimal format by simply multiplying by 100
0.375 * 100, is 37.5%
the new size of "ab" is just 37.5% of the original "ab"
it decreased by 100 - 37.5 or 62.5%
"Combinations" isn't really the right word, because a combination doesn't take order of elements into account, and the outcome of a race certainly does depend on order. "Permutations" would be the correct term.
If 4 students are competing, then the race has
4! = 4 • 3 • 2 • 1 = 24
possible outcomes.
Answer:
is the answer
Step-by-step explanation:
Equation of the line: y = 6/5x + 1
= 5y = 6x + 5
= 6x - 5y + 5
Equation of the perpendicular line: bx - ay + k = 0
= -5x -6y + k = 0
Equation passes through (6,-6),
-5(6) -6(-6) + k = 0
-30 + 36 + k = 0
6 + k = 0
k = -6
Substituting,
-5x -6y + k = 0
-5x -6y -6 = 0
-6y = 5x + 6
(Slope-Intercept form)
I’m not really sure but I would have to guess 4.5 because all of the other numbers don’t have decimals
Answer:
<h3>B. It has infinite solutions</h3>
Step-by-step explanation:
Given the system of equations:
2t + w = 10 ..... 1
4t = 20 − 2w ... 2
From 1:
w = 10-2t ...3
Substitute 3 into 2 to have;
4t = 20 - 2(10-2t)
4t = 20-20+4t
4t = 4t
Let t = k
Substitute t = k into 1 and get w;
From 1: 2t + w = 10
2k + w =10
w = 10 - 2k
<em>k can take any integers. This shows that the solution to the equation is infinite</em>
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