Answer:
The remainder is -2.
Step-by-step explanation:
According to the Polynomial Remainder Theorem, if we divide a polynomial P(x) by a binomial (<em>x</em> - <em>a</em>), then the remainder of the operation will be given by P(a).
Our polynomial is:
And we want to find the remainder when it's divided by the binomial:
We can rewrite our divisor as (<em>x</em> - (-1)). Hence, <em>a</em> = -1.
Then by the PRT, the remainder will be:
The remainder is -2.
Answer:
x = 21.013155617496
Step-by-step explanation:
we have a right triangle then ,
Then
Then
x ≈ 21
To get the solution we are looking for we need to point out what we know.
1. We assume that 55 is 100% because its the output value of the task.
2. We assume that the x is the value we are looking for.
3. If 100% = 55 so we can write it down as 100%=55
4. We know that x% = 44 of the output value so we can write it as x%=44.
5. Now we have two simple equations: 1) 100%=55 2) x%=44 where left sides of both of them have the same units and both right sides have the same units so we can do something like that 100%/x%=55/44.
6. Now we just have to solve the simple equation and we will get the answer.
7. Solution for 44 is what percent of 55 100%/x%=55/44 (100/x)*x=(55/44)*x we multiply both sides of the equation by x 100= 1.25*x we divide both sides of the equation by (1.25) to get x 100/1.25=x 80=x now we have: 44 is 80% of 55!
Quick answer = 44 is 80% of 55
Hope this helps! ;D
-5x^3 + 2x^2 + 1
a coefficient is the number that is multiplied by the variable.For instance, the coefficient of 2x is 2....because 2 (the number) is multiplied by the variable x.
so in ur problem....there are 2 coefficients..-5 and 2.
** the number 1 is not a coefficient, it is a constant...a " loner " with no variables (letters) attached.
** and if u have just the letter...such as n, the coefficient to that is 1 but the one is just not written...it is actually 1n.
okay...I am gonna shut up now :)
ANSWER
EXPLANATION
The given expression is
We factor to get,
This implies that,
We factor further to obtain,
or
