I think the answer is B im not sure :(
Answer:
V = ∫∫∫rdrdθdz integrating from z = 2 to z = 4, r = 0 to √(16 - z²) and θ = 0 to 2π
Step-by-step explanation:
Since we have the radius of the sphere R = 4, we have R² = r² + z² where r = radius of cylinder in z-plane and z = height² of cylinder.
So, r = √(R² - z²)
r = √(4² - z²)
r = √(16 - z²)
Since the region is above the plane z = 2, we integrate z from z = 2 to z = R = 4
Our volume integral in cylindrical coordinates is thus
V = ∫∫∫rdrdθdz integrating from z = 2 to z = 4, r = 0 to √(16 - z²) and θ = 0 to 2π
Answer:
The answer is -1.2
Step-by-step explanation:
Recalling the standard deviation formula,
we have : σ = sqrt[ P * ( 1 - P ) / n ]
Where sqrt = square root
n = Number of derivative
Therefore,:
if, H0: p is not 48% vs H1: p1 = 48%
standard deviation is:
σ = sqrt[ P * ( 1 - P ) / n ] = sqrt[ .48*.49/900 ] = .01666333+
z -score is (p-P)/σ
= (.51-.53)/.01666333
The answer therefore = -1.2
ICONCLUSION:
It can therefore be concluded that there is statistical evidence that the proportions are different. H0 accepted in the hypothesis.
Answer:
15 3/4t^2 + 5 1/4
Explanation:
h(t)=-16t^2+400
We can add 400 then - 64 and show as 8^2
= h(t)=-16t^2+400 - 8^2
But we also need to change 16t^2;
We divide 64 into 16 = 16/64 =0.25
and show 16t^2 changes by 0.25 = 1/4
15 3/4t^2 + 400-64
Can now look like
15 3/4t^2 + 5 1/4
As 5 1/4 = 64 x 5 1/4 = 336
Answer:
7/10 or 70%
Step-by-step explanation:
Add the number of each color of balls together to get the total
5 + 2 + 3 = 10
Add the number of all the balls that aren't black
5 + 2 = 7
Then divide how many balls that aren't black by the total. This gives us the probability the ball you choose is not black
7/10 = 0.7 or 70%
