All categories

2 years ago

What is the slope intercept form of the equation 2y+3x=-8

Mathematics

2 answers:

antoniya [11.8K]2 years ago

8 0

Answer:

y=-1.5x-4

Step-by-step explanation:

Slope intercept form is y=mx+b

Bring x over to the other side

2y=-8-3x

divide by 2

y=-4-1.5x

y=-1.5x-4 should be your equation in slope-intercept form

BARSIC [14]2 years ago

7 0

Answer:

Step-by-step explanation:

Slope intercept form : y = mx+ b

2y + 3x = -8

2y = -3x - 8

Divide the entire equation by 2

$\dfrac{2y}{2}= \dfrac{-3}{2}x- \dfrac{8}{2}\\\\y= \dfrac{-3}{2}x - 4$

You might be interested in

A boat captain can see a lighthouse on the shore which is 103ft in front of him. If the lighthouse is 22ft tall, at what angle o

elena-14-01-66 [18.8K]

Answer:

21°

Step-by-step explanation:

A boat captain, lighthouse and its base form a right triangle.

We need to find the angle opposite to 22 ft side:

tan x = 22/103
x = arctan (22/103)
x = 21°

Note, option D should read 21° not 11°

5 0

2 years ago

Which of the following are identities? Check all that apply

Natasha2012 [34]

Answer:

A, C

Step-by-step explanation:

Actually, those questions require us to develop those equations to derive into trigonometrical equations so that we can unveil them or not. Doing it only two alternatives, the other ones will not result in Trigonometrical Identities.

Examining

A) True

$\frac{1-tan^{2}x}{2tanx} =\frac{1}{tan2x} \\ \frac{1-tan^{2}x}{2tanx} =\frac{1}{\frac{2tanx}{1-tan^{2}x}}\\ tan2x=\frac{1-tan^{2}x}{2tanx}$

Double angle $tan2\alpha =\frac{1 -tan^{2}\alpha }{2tan\alpha}$

B) False,

No further development towards a Trig Identity

C) True

Double Angle Sine Formula $sin2\alpha =2sin\alpha *cos\alpha$

$sin(8x)=2sin(4x)cos(4x)\\2sin(4x)cos(4x)=2sin(4x)cos(4x)$

D) False No further development towards a Trig Identity

$[sin(x)-cos(x)]^{2} =1+sin(2x)\\ sin^{2} (x)-2sin(x)cos(x)+cos^{2}x=1+2sinxcosx\\ \\sin^{2} (x)+cos^{2}x=1+4sin(x)cos(x)$

7 0

3 years ago

Read 2 more answers

If r(x) = 2 – x2 and w(x) = x – 2, what is the range of (w circle r) (x)?

VashaNatasha [74]

Answer:

$(-\infty, 0)$

Step-by-step explanation:

(w circle r) (x) is the composite function(w of r(x)), that is, w(r(x))[/tex]

We have that:

$r(x) = 2 - x^{2}$

$w(x) = x - 2$

Composite function:

$w(r(x)) = w(2 - x^{2}} = 2 - x^{2} - 2 = -x^{2}$

$-x^{2}$ is a negative parabola with vertex at the original.

So the range(the values that y assumes), is:

$(-\infty, 0)$

3 0

3 years ago

Read 2 more answers

Evaluate 5x 2+ 2(4x – 7) – 8x for x = 3.

Sauron [17]

Answer:

10x-14

Step-by-step explanation:

6 0

2 years ago

Evaluate the expressions for when x=-1, y=3, z=-2 z²+(x²)-y and x²(y²)(z²)

inessss [21]

Answer:

Use https://www.bartleby.com/ it has helped me out a lot . Its actual tutors/teachers who answer your questions in about 30 minutes :)

Step-by-step explanation:

4 0

3 years ago