Acids react with calcium carbonate and more specifically carbonate to form carbon dioxide. An acid will give protons to the carbonate anion to produce carbonic acid which then decomposes into carbon dioxide and water. I hope this helps. Let me know if anything is unclear.
The correct answers is 1/57
Answer: 15.8 g of
will be required to produce 1.60 grams of 
Explanation:
To calculate the moles :

According to stoichiometry :
As 1 mole of
is given by = 2 moles of 
Thus 0.05 moles of
is given by =
of 
Mass of 
Thus 15.8 g of
will be required to produce 1.60 grams of 
I am not sure about my answer, but I think that it's density allows it to fall to the ground/floor.