What are the measures of the angles in the triangle?

Mathematics

1 answer:

Ierofanga [76]3 years ago

8 0

Answer:

u need to put a picture so we know what your talking about

You might be interested in

3(2x+7)+15-2x what is the answer to this

sp2606 [1]

6x+21+15-2x
4x+36
hope this helps...

3 0

3 years ago

Read 2 more answers

A textbook store sold a combined total of 260 chemistry and physics textbooks in a week. The number of chemistry books sold was

Lynna [10]

Let:

x = Chemistry textbooks sold

y = Physics textbooks sold

The textbook store sold a combined total of 260, so:

$x+y=260$

The number of chemistry books sold was three times the number of physics textbooks sold, so:

$x=3y$

Let:

$\begin{gathered} x+y=260_{\text{ }}(1) \\ x=3y_{\text{ }}(2) \end{gathered}$

Replace (2) into (1):

$\begin{gathered} 3y+y=260 \\ 4y=260 \\ y=\frac{260}{4} \\ y=65 \end{gathered}$

Replace the value of y into (2):

$\begin{gathered} x=3(65) \\ x=195 \end{gathered}$

5 0

1 year ago

(a) The parametric equations x = f(t) and y = g(t) give the coordinates of a point (x, y) = (f(t), g(t)) for appropriate values

Gnesinka [82]

Answer:

Step-by-step explanation:

a). Given a parametric equation, we are describing a set of coordinates based on the value of t. The variable t is called the parameter.

b) we have the following equations. x=t y=t^2, so in order for us to know where the object is at t=t' we must replace t with the specific value t'. Hence, when t=0 the object is at (0,0^2) = (0,0) (the origin). When t=6, the object is at (6,6^2) = (6,36).

c). To eliminate the parameter, we replace the parameter in one equation by using the second equation. Recall that we have that x=t. Then, by replacing in the second equation, we have the following

$y=t^2 = (x)^2 = x^2$