1. m∠1 + m∠2 = 180°
2. Definition of bisector
3. m∠1 + m∠3 = 180°
4. Substitution Property of Equality
Answer:5
Step-by-step explanation:
Answer:Y=25:3
Step-by-step explanation:
Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
Answer:
3
Step-by-step explanation:
The average rate of change is
f(x2) - f(x1)
-----------------
x2-x1
We want to find the change from 1 to 3
f(3) = 8
f(1) = 2
f(3) - f(1) 8-2 6
----------------- = ------------ = ---- = 3
3-1 2 2
