Given:
The function is:
To find:
The initial value of the function.
Solution:
We have,
The value of the function at x=0 is called the initial value of the function.
For x=0, we get
Clearly 0.88 is a non zero number and zero to the power of a non zero number is always 1.
Therefore, the initial value of the function is 350.
No real solutions. x2−
[email protected]−12x+59=0x2−12x+59=0Step 1: Use quadratic formula with a=1, b=-12, c=59.x=−b±√b2−4ac2ax=−(−12)±√(−12)2−4(1)(59)2(1)x=12±√−922
For this case we must compare the following expressions:
We convert the mixed number to a fraction:
So, we have to compare:
1.2 and 1.2
It is observed that the expressions are equal, so we have the sign of equality "=":
Answer:
