1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kodGreya [7K]
2 years ago
12

Help on this, please

Mathematics
2 answers:
Nadusha1986 [10]2 years ago
6 0
Cp akosmw’msoswkqowmw’sm2skz
zzzjonxdnej up oompdj8)h9
faust18 [17]2 years ago
3 0

Answer:

    C.P                                          Discount                                           S.P

3) $450                                            80%                                             $90

4) $200                                            64%                                             $72

Step-by-step explanation:

Please give me brainliest :)

You might be interested in
PLZ HELP, AND PLZ EXPLAIN
shutvik [7]

Answer:

C

Step-by-step explanation:

To make it easy let's start by organizing our information :

  • AC=12 AND BD=8
  • ABCD is a rhombus
  • K and L are the midpoints of sides AD and CD
  • we notice that the rhombus ABCD is divided into four right triangles

What do you think of when you hear a right triangle ?

  • The pythagorian theorem !

AC and BD  are khown so let's focus on them .

If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?

Simply because they are the diagonals of a rhombus .

ow let's apply the pythagorian theorem :

  • (AC/2)² + (BD/2)² = BC²
  • 6²+4²=52
  • BC²= 52⇒\sqrt{52}=BC

Now we khow that : AB=BC=CD=AD=\sqrt{52}

This isn't enough . Let's try to figure out a way to calculate the length of KL  wich is the base of the triangle

  • KL is parallel to AC
  • k is the midpoint of AD and L of DC

I smell something . yes! Thales theorem

  • KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
  • KL/12=\sqrt{52}/2*\sqrt{52}  
  • KL/12=1/2⇒ KL=6

Now we have the length of the base kl

Now the big boss the height :

  • notice that you khow the length of KL
  • BD crosses kl from its midpoint and DL = \sqrt{52} /2

What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D

  • DL²=(KL/2)²+D²
  • 52/4= 9+ D²
  • D² = 52/4-9 +4 SO D=2

now the height of the trigle is H= BD-D= 8-2=6

NOw the area of the triangle is :

  • A=(KL*H)/2 ⇒ A= (6*6)/2=18

THE ANSWER IS 18 SQ.UN

5 0
3 years ago
A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y = 5 − x 2 . What are the dimensions
kherson [118]

Answer:

A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola

y=5−x^2. What are the dimensions of such a rectangle with the greatest possible area?

Width =

Height =

Width =√10 and Height = \frac{10}{4}

Step-by-step explanation:

Let the coordinates of the vertices of the rectangle which lie on the given parabola y = 5 - x² ........ (1)

are (h,k) and (-h,k).

Hence, the area of the rectangle will be (h + h) × k

Therefore, A = h²k ..... (2).

Now, from equation (1) we can write k = 5 - h² ....... (3)

So, from equation (2), we can write

A =h^{2} [5-h^{2} ]=5h^{2} -h^{4}

For, A to be greatest ,

\frac{dA}{dh} =0 = 10h-4h^{3}

⇒ h[10-4h^{2} ]=0

⇒ h^{2} =\frac{10}{4} {Since, h≠ 0}

⇒ h = ±\frac{\sqrt{10} }{2}

Therefore, from equation (3), k = 5 - h²

⇒ k=5-\frac{10}{4} =\frac{10}{4}

Hence,

Width = 2h =√10 and

Height = k =\frac{10}{4}.

8 0
3 years ago
Given that the triangles shown below are simiar, what is the value of x?
mina [271]

Answer:

B

Step-by-step explanation:

This triangle has been scaled down from triangle one to triangle two. I didn't have a lot of study on this subject, but the answer that makes most sense to me would be B if you want to keep the triangles proportional

6 0
2 years ago
PLEASE I GIVE BRAINLIRST PLEASE HELP I NEED TO OASS THIS
aalyn [17]

Answer:

Evan needs enough paint to cover 448in^2

He needs enough soil to fill 768in^3

Step-by-step explanation:

7 0
2 years ago
How to write a quadratic function when given the axis of symmetry?
shutvik [7]
<span>Are you from Connections Academy, public school or any other online school? Then join our discord, we help each other out with homework and just chill. discord. gg/ qZcMArh (make sure to remove the spaces) WE also have our own tutors that can help you! (if the discord link didn't work add ugly guy#1805 on discord. ( we're also a active group that requires a verified email to join due to trolls. It's not hard to do thankfully just go to discord app and sign up : ) |) Connections Academy Discord Online School Discord Homework Help Discord Connexus Discord Public School Discord Connections Discord Academy Discord Connections Academy Reddit Connexus Reddit Connexus Connections Academy Instagram Connections Academy Twitter Connexus homeschool discord homeschool reddit connections academy twitter connections academy discord</span>
3 0
3 years ago
Other questions:
  • 9+(-3)=______________
    5·2 answers
  • he √ symbol is called the ___________________. The number or expression beneath the √ symbol is called the ___________________.
    12·1 answer
  • Need help with this math problem
    11·1 answer
  • 20 POINTS AND BRAINLIEST !! PLEASE ANSWER THIS MATH QUESTION !!
    7·1 answer
  • 3 more than a number divided by 12 equals to 40, turn this phase into a algebraic equation.
    6·1 answer
  • Don’t mind the writing. Just trying to see if this is right?
    5·2 answers
  • what is the correct form of the partial fraction decomposition for: start fraction 35-27x over 4xsquared+28x endfraction
    6·2 answers
  • I need help i’m not good at math
    7·1 answer
  • Mr. Lai buys 2 1/4 pounds of red apples and 1 3/8 pounds of green apples. How many more pounds of red apples does he buy?
    15·1 answer
  • URGENT this is a question on my precalculus test I need help on. Thank you so much
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!