Answer:
1,2 and 4 are conservatives
3 is not conservative
Step-by-step explanation:
We calculate the Curl F
Remember that:
Curl F = <>
1. Curl F = <0,0,5-5> = <0,0,0>
The potential function f so that ∇f=F
f(x,y,z) =
Then F is conservative
2. Curl F = < 0, 0 ,0>
The potential function f so that ∇f=F
f(x,y,z) =
Then F is conservative
3. Curl F = <0 ,0, 10+3xsin(y) - (-cos(y))>
= <0 ,0 , 10 +3xsin(y) + cos(y)<
How the field's divergence is not zero the vector field is not conservative
4. Curl F = <0, 0, 0>
The potential function f so that ∇f=F
f(x,y,z) =
Then F is conservative
