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Sindrei [870]
2 years ago
6

Two similar triangles are shown below which two sets of angles are corresponding angles p and q

Mathematics
1 answer:
Oduvanchick [21]2 years ago
6 0

Answer:   p = 30  q = 30 (if not touching edge of hexagon but if it is touching edge one of the pairs) then p or q = 120  and p and q = 30

Step 1)  Sum of an interior angle of a polygon = 720 degree where n = 6 as 6 exterior sides =  (n-2) * 180 = (6-2) * 180 = 4 * 180 = 720 degree   Where the measure of each angle of a hexagon = 720/ 6 = 120 degree   Step 2) Then show 3 angle letter names = 180 degree     Step 3) Angle name letters + 2 angle (other two names letters inside within triangle) add up to 180 degree    Step 3) State since triangle name (of all letters within one triangle) is Isosceles   Step 4) <u>Triangle (state same triangle letters with number 2 in front) = 180 - 120 = 60  then state triangle (letter name) / 2 = 30 degrees </u>obviously the 120 and 60 differentiates if not a hexagon to a pentagon if not a hexagon =  (3 *180) / 5 = 108  then due to isosceles (180 - 108)/ 2  = 72/2 = 36 degree for a p<u>entagon </u>or 30 degree each for p + q for a <u>hexagon</u> etc

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A semicircle with diameter PQ sits on an isosceles triangle PQR to form a region shaped like a two-dimensional ice- cream cone,
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The limit of a(x)/b(x) as x approaches 0 is gotten as;

lim a(x)/b(x); x→0 = 0

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  • From the image, ∠PQR = θ

Thus; a(x) = ¹/₂π(10 sin (θ/2))²

a(x) =  ¹/₂π(100 sin² (θ/2))

Similarly;

b(x) =  ¹/₂(20 sin (θ/2)) × (10 cos (θ/2))

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  • Thus;

a(x)/b(x) = ¹/₂π(100 sin² (θ/2)) ÷ 100 sin (θ/2) cos (θ/2)

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upon further simplification to give;

a(x)/b(x) = ¹/₂π(sin (θ/2)) ÷ cos (θ/2)

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Thus;

a(x)/b(x) = ¹/₂π(sin (θ/2)) ÷ cos (θ/2) =  ¹/₂π(tan (θ/2))

We want to find the limit as θ approaches <em>zero.</em>

Thus;

lim θ → 0 =  ¹/₂π(tan (0/2))

⇒ ¹/₂π tan 0

⇒ 0

Read more at; https://brainly.in/question/9387458

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Read 2 more answers
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