The correct answer is D.
The solutions are where the points where they both intersect
Answer: The probability that a randomly selected adult doesn’t regularly consume at least one of these two products is 30%
Be:
A: Adults regularly consume coffee
B: Adults regularly consume carbonated soda
C: Adults doesn't regularly consume at leas one of these two products.
55% of all adults regularly consume coffee→P(A)=55%=55/100→P(A)=0.55
45% regularly consume carbonated soda→P(B)=45%=45/100→P(B)=0.45
70% regularly consume at least one of these two products→P(A U B)=70%=70/100→P(A U B)=0.70
a) What is the probability that a randomly selected adult regularly consumes both coffee and soda?
P(A ∩ B)=?
P(A U B)=P(A) + P(B) - P(A ∩ B)
Replacing P(A U B)=0.70; P(A)=0.55; and P(B)=0.45 in the equation above:
0.70=0.55 + 0.45 - P(A ∩ B)→
0.70=1.00 - P(A ∩ B)
Solving for P(A ∩ B): Subtracting 1.00 both sides of the equation:
0.70-1.00=1.00 - P(A ∩ B) -1.00→
-0.30 = - P(A ∩ B)
Multiplying both sides of the equation by (-1):
(-1)(-0.30) = (-1)[ - P(A ∩ B)]→
0.30 = P(A ∩ B)→
P(A ∩ B) =0.30→
P(A ∩ B) = (0.30)*100%→
P(A ∩ B) = 30%
Answer: The probability that a randomly selected adult regularly consumes both coffee and soda is 70%
b. What is the probability that a randomly selected adult doesn’t regularly consume at least one of these two products?
P(C)=?
P(A U B) + P(C)=1
Replacing P(A U B)= 0.70 in the equation above:
0.70+P(C)=1
Solving for P(C). Subtracting 0.70 both sides of the equation:
0.70+P(C)-0.70=1-0.70→
P(C)=0.30→
P(C)=(0.30)*100%→
P(C)=30%
Answer: The probability that a randomly selected adult doesn’t regularly consume at least one of these two products is 30%
Answer:
Step-by-step explanation: 12,061
Answer: C
Step-by-step explanation: 8 (1/3) 16 (2/3) 24 (3/3)
Convert <span>6\frac{3}{8}<span>6<span><span>8</span><span>3</span><span></span></span></span></span><span> to improper fraction. Use this rule: </span><span>a \frac{b}{c}=\frac{ac+b}{c}<span>a<span><span>c</span><span>b</span><span></span></span>=<span><span>c</span><span><span>ac+b</span></span>:</span></span></span>
∣8<span><span><span><span>6×8+3</span></span><span></span></span>−2∣+∣−8<span><span>8</span><span>5</span><span></span></span>−1<span>∣
</span></span>Simplify <span>6\times 8<span>6×8</span></span><span> to </span>48: <span><span><span><span><span>
</span>8</span><span><span>48+3</span></span><span></span></span>−2∣+∣−8<span><span>8</span><span>5</span><span></span></span>−1∣
</span>Simplify <span>48+3<span>48+3</span></span><span> to </span>51:</span><span><span><span><span><span>
</span>8</span><span><span>51</span></span><span></span></span>−2∣+∣−8<span><span>8</span><span>5</span><span></span></span>−1∣
</span> Make the denominators the same:
<span><span><span>51</span><span>/8</span></span>−2×<span><span>8</span><span>8</span><span>
</span></span></span><span>Simplify. Denominators are now the same:
</span>
<span><span><span>51</span><span>/8</span></span>−<span><span>8</span><span><span>16</span></span><span>
</span>
</span></span>Join the denominators: \frac{51-16}{8}<span><span>8</span><span><span>51−16</span></span><span>
</span>
etc.. and your answer will be 14
</span></span>