Answer:
-22°F < x < 266°F.
Step-by-step explanation:
The question states the incorrect formula to convert the Celsius temperature (C) into the Fahrenheit temperature (F). The correct one is given by:
F = 9C/5 + 32.
The given temperature inequality in Celsius is:
-30°C < x < 130°C; where x is any number that satisfies the inequality.
To convert it into Fahrenheit, simply plug in the values in the above formula.
Lower Limit:
F = 9(-30)/5 + 32.
F = -54 + 32.
F = -22°F.
Upper Limit:
F = 9(130)/5 + 32.
F = 234 + 32.
F = 266°F.
Therefore, the inequality will be -22°F < x < 266°F!!!
Answer:
59
Step-by-step explanation:
just add the 2 and you should get 59
Answer:
y = 4
Step-by-step explanation:
because 5 x 4 = 20 and 20 × 4 = 80 and so on y is equal to four
a. The
component tells you the particle's height:
![3t=16\implies t=\dfrac{16}3](https://tex.z-dn.net/?f=3t%3D16%5Cimplies%20t%3D%5Cdfrac%7B16%7D3)
b. The particle's velocity is obtained by differentiating its position function:
![\vec v(t)=\dfrac{\mathrm d\vec r(t)}{\mathrm dt}=-\sin t\,\vec\imath+\cos t\,\vec\jmath+3\,\vec k](https://tex.z-dn.net/?f=%5Cvec%20v%28t%29%3D%5Cdfrac%7B%5Cmathrm%20d%5Cvec%20r%28t%29%7D%7B%5Cmathrm%20dt%7D%3D-%5Csin%20t%5C%2C%5Cvec%5Cimath%2B%5Ccos%20t%5C%2C%5Cvec%5Cjmath%2B3%5C%2C%5Cvec%20k)
so that its velocity at time
is
![\vec v\left(\dfrac{16}3\right)=-\sin\dfrac{16}3\,\vec\imath+\cos\dfrac{16}3\,\vec\jmath+3\,\vec k](https://tex.z-dn.net/?f=%5Cvec%20v%5Cleft%28%5Cdfrac%7B16%7D3%5Cright%29%3D-%5Csin%5Cdfrac%7B16%7D3%5C%2C%5Cvec%5Cimath%2B%5Ccos%5Cdfrac%7B16%7D3%5C%2C%5Cvec%5Cjmath%2B3%5C%2C%5Cvec%20k)
c. The tangent to
at
is
![\vec T(t)=\vec r\left(\dfrac{16}3\right)+\vec v\left(\dfrac{16}3\right)t](https://tex.z-dn.net/?f=%5Cvec%20T%28t%29%3D%5Cvec%20r%5Cleft%28%5Cdfrac%7B16%7D3%5Cright%29%2B%5Cvec%20v%5Cleft%28%5Cdfrac%7B16%7D3%5Cright%29t)