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Firlakuza [10]
2 years ago
8

Which is equivalent to 3 square foot of 8 1/4 x

Mathematics
1 answer:
Oxana [17]2 years ago
6 0

( \sqrt[3]{8}) \frac{1}{4} x = 8 \frac{1}{3}  \frac{1}{4} x = 8 \frac{1}{12} x = ( \sqrt[12]{8}
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Help please thanks show work
marshall27 [118]

Answer:

x = 18

Step-by-step explanation:

7x - 24 is a verticasl angle with an angle that is an...

Alternate interior angle with the combines values of 49 and 3x so they  are equal

49 + 3x = (7x -23)

72 = 4x

x = 18

6 0
3 years ago
rationalize the dominator and simplify the following expressions into the simplest possibke surds: i. 8/√2 + 2√50​
Akimi4 [234]

Answer:

8/√2 + 2√50​

8√2/2 + 2√50

4√2 + 10√2

<u>14√2</u>

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3 years ago
Solve for a: a - 17 = -10
alexandr402 [8]

Answer:

a = 7

Step-by-step explanation:

a - 17 = -10

Add 17 to each side

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3 years ago
Read 2 more answers
An object is launched from ground level with an initial velocity of 120 meters per second. For how long is the object at or abov
babunello [35]

Answer:

D) 14 seconds

Step-by-step explanation:

First we will plug 500 in for y:

500 = -4.9t² + 120t

We want to set this equal to 0 in order to solve it; to do this, subtract 500 from each side:

500-500 = -4.9t² + 120t - 500

0 = -4.9t²+120t-500

Our values for a, b and c are:

a = -4.9; b = 120; c = -500

We will use the quadratic formula to solve this.  This will give us the two times that the object is at exactly 500 meters.  The difference between these two times will tell us when the object is at or above 500 meters.

The quadratic formula is:

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Using our values for a, b and c,

x=\frac{-120\pm \sqrt{120^2-4(-4.9)(-500)}}{2(-4.9)}\\\\=\frac{-120\pm \sqrt{14400-9800}}{-9.8}\\\\=\frac{-120\pm \sqrt{4600}}{-9.8}\\\\=\frac{-120\pm 67.8233}{-9.8}\\\\=\frac{-120+67.8233}{-9.8}\text{ or }\frac{-120-67.8233}{-9.8}\\\\=\frac{-57.1767}{-9.8}\text{ or }\frac{-187.8233}{-9.8}\\\\=5.3242\text{ or }19.1656

The two times the object is at exactly 500 meters above the ground are at 5 seconds and 19 seconds.  This means the amount of time it is at or above 500 meters is

19-5 = 14 seconds.

6 0
3 years ago
Quadrilaterals Graphic Organizer
Taya2010 [7]

#Trapezoid

  • One pair of opposite sides of parallel
  • All angles are unsimilar and sum of angles are 360°.

#Parallelogram

  • Two pair of opposite sides are parallel and same.
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#Rectangles:-

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#Square:-.

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6 0
2 years ago
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