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velikii [3]
3 years ago
6

Find a counterexample to show the conjecture is false

Mathematics
1 answer:
EleoNora [17]3 years ago
8 0

Answer:

Step-by-step explanation:

If two angles are supplement of each other then one of the angles must be acute

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lions [1.4K]

Answer:

10.2

Step-by-step explanation:

7 0
3 years ago
Linear Relationships Study Guide 1.) Select all the equations for which (-6, -1) is a solution. Show your work to prove that eac
TiliK225 [7]

we have point (-6, - 1)

Now we will put these points in each equation,

y = 4x +23

put x = -6 and y = -1

-1 = 4 (-6) +23

-1 = -24 + 23

-1 = -1

LHS = RHS, so this equation has (-6 , -1) as solution.

y = 6x

put x = -6 and y = -1

-1 = 6 (-6)

-1 not= -36

LHS is not equal RHS, so (-6 , -1) is not a solution for that equation,

y = 3x - 5

put x = -6 and y = -1

-1 = 3 (-6) - 5

-1 = -18 - 5

-1 not= -23

LHS is not equal RHS, so (-6 , -1) is not a solution for that equation,

y= 1/6 x

put x = -6 and y = -1

-1 = -6/6

-1 = -1

LHS = RHS, so (-6 , -1) is a solution for that equation,

6 0
1 year ago
Q3) f(x) 2x^2 - 5x, g(x) = 3x^3 find g(4x)
mrs_skeptik [129]

Answer:

g(4x) = 192x^3

Step-by-step explanation:

For this problem, f(x) is irrelevant since we are simply are dealing with g(x).  We will simply replace the value of x in g(x) with 4x.  So let's do that.

g(x) = 3x^3

g(4x) = 3(4x)^3

g(4x) = 3(4^3)(x^3)

g(4x) = 3(64)(x^3)

g(4x) = 192x^3

Hence, g(4x) is 192x^3.

Cheers.

4 0
3 years ago
There are 12 marbles in a box. 8 are purple, and 4 are green. What is the probability of picking a purple marble and then a gree
Bad White [126]

Answer: 8/33

Step-by-step explanation:

So the probability of picking a purple marble is 8/12, after that there are 11 marbles left in the box

Now the probability of picking a green marble without placing the first marble back is 4/11

So the probability of doing both is 8/12 x 4/11 = 8/33

8 0
2 years ago
At a dog park , there are 10 black dogs, 5 brown dog, 2 white dog, and 12 multi color dogs​
Sophie [7]
What question are you trying to ask?
5 0
3 years ago
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