Answer:
10.2
Step-by-step explanation:
we have point (-6, - 1)
Now we will put these points in each equation,
y = 4x +23
put x = -6 and y = -1
-1 = 4 (-6) +23
-1 = -24 + 23
-1 = -1
LHS = RHS, so this equation has (-6 , -1) as solution.
y = 6x
put x = -6 and y = -1
-1 = 6 (-6)
-1 not= -36
LHS is not equal RHS, so (-6 , -1) is not a solution for that equation,
y = 3x - 5
put x = -6 and y = -1
-1 = 3 (-6) - 5
-1 = -18 - 5
-1 not= -23
LHS is not equal RHS, so (-6 , -1) is not a solution for that equation,
y= 1/6 x
put x = -6 and y = -1
-1 = -6/6
-1 = -1
LHS = RHS, so (-6 , -1) is a solution for that equation,
Answer:
g(4x) = 192x^3
Step-by-step explanation:
For this problem, f(x) is irrelevant since we are simply are dealing with g(x). We will simply replace the value of x in g(x) with 4x. So let's do that.
g(x) = 3x^3
g(4x) = 3(4x)^3
g(4x) = 3(4^3)(x^3)
g(4x) = 3(64)(x^3)
g(4x) = 192x^3
Hence, g(4x) is 192x^3.
Cheers.
Answer: 8/33
Step-by-step explanation:
So the probability of picking a purple marble is 8/12, after that there are 11 marbles left in the box
Now the probability of picking a green marble without placing the first marble back is 4/11
So the probability of doing both is 8/12 x 4/11 = 8/33
What question are you trying to ask?