We need Pythagoras theorem here
a^2+b^2 = c^2
a, b = legs of a right-triangle
c = length of hypotenuse
Let S=shorter leg, in cm, then longer leg=S+2 cm
use Pythagoras theorem
S^2+(S+2)^2 = (10 cm)^2
expand (S+2)^2
S^2 + S^2+4S+4 = 100 cm^2 [collect terms and isolate]
2S^2+4S = 100-4 = 96 cm^2
simplify and form standard form of quadratic
S^2+2S-48=0
Solve by factoring
(S+8)(S-6) = 0 means (S+8)=0, S=-8
or (S-6)=0, S=6
Reject nengative root, so
Shorter leg = 6 cm
Longer leg = 6+2 cm = 8 cm
Hypotenuse (given) = 10 cm
Well, for wheel 1, divide 1/3 to get .3333333333333333
for wheel 2, divide 1/4 to get .25
hope this helps
Answer:
16.02
Step-by-step explanation:
2. What inference can you make by comparing the measures
of variability?
I need the answer
16.02
Answer:
A 1/4
Step-by-step explanation:
2/3 x = 1/6
2x/3 = 1/6
2x/3 = 1/2x3
The answer is 1/4
140a/35s=4a/s
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