Find the slope m.
Use the point-slope formula.
Solve for y.
The area of the circle is 28 ft square.
The area of the triangle is 30 ft square.
Step-by-step explanation:
1) The area of the circle= π*r^2
where π= 3.14(default value) and "r" is the radius of the circle.
Here, Radius of the circle(r)= 3 ft
Area = 3.14*3*3
= 28.26 ft sq.= 28 ft sq(rounded to the nearest whole number)
2) The triangle has the base= 10 feet and height= 6 feet
The Area of the triangle= 1/2(b)(h)
where "b" is the base and "h" is the height of the triangle.
Substitute b=10 and h=6 ,
Area of triangle= 1/2(10 ft)(6 ft)= 60/2= 30 feet sq.
Answer:
32.66 units
Step-by-step explanation:
We are given that

Point A=(-2,-4) and point B=(1,20)
Differentiate w.r. t x

We know that length of curve

We have a=-2 and b=1
Using the formula
Length of curve=
Using substitution method
Substitute t=12x+14
Differentiate w.r t. x


Length of curve=
We know that

By using the formula
Length of curve=![s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}](https://tex.z-dn.net/?f=s%3D%5Cfrac%7B1%7D%7B12%7D%5B%5Cfrac%7Bt%7D%7B2%7D%5Csqrt%7B1%2Bt%5E2%7D%2B%5Cfrac%7B1%7D%7B2%7Dln%28t%2B%5Csqrt%7B1%2Bt%5E2%7D%29%5D%5E%7B1%7D_%7B-2%7D)
Length of curve=![s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}](https://tex.z-dn.net/?f=s%3D%5Cfrac%7B1%7D%7B12%7D%5B%5Cfrac%7B12x%2B14%7D%7B2%7D%5Csqrt%7B1%2B%2812x%2B14%29%5E2%7D%2B%5Cfrac%7B1%7D%7B2%7Dln%2812x%2B14%2B%5Csqrt%7B1%2B%2812x%2B14%29%5E2%7D%29%5D%5E%7B1%7D_%7B-2%7D)
Length of curve=
Length of curve=
Length of curve=
I believe the answer is BC, AB, AC