Answer:
- P(≥1 working) = 0.9936
- She raises her odds of completing the exam without failure by a factor of 13.5, from 11.5 : 1 to 155.25 : 1.
Step-by-step explanation:
1. Assuming the failure is in the calculator, not the operator, and the failures are independent, the probability of finishing with at least one working calculator is the complement of the probability that both will fail. That is ...
... P(≥1 working) = 1 - P(both fail) = 1 - P(fail)² = 1 - (1 - 0.92)² = 0.9936
2. The odds in favor of finishing an exam starting with only one calculator are 0.92 : 0.08 = 11.5 : 1.
If two calculators are brought to the exam, the odds in favor of at least one working calculator are 0.9936 : 0.0064 = 155.25 : 1.
This odds ratio is 155.25/11.5 = 13.5 times as good as the odds with only one calculator.
_____
My assessment is that there is significant gain from bringing a backup. (Personally, I might investigate why the probability of failure is so high. I have not had such bad luck with calculators, which makes me wonder if operator error is involved.)
We know that the perimeter of a rectangle = 2(l + w)
l = length
w = width
In our problem,
l = 5x
w = 5x - 4
Let's create an inequality to help us solve this problem.
2(5x + (5x - 4)) ≥ 96
Let's start off by simplifying the terms inside the parentheses.
2(10x - 4) ≥ 96
Distribute the 2
20x - 8 ≥ 96
Add 8 to both sides.
20x ≥ 104
Divide both sides by 20
x ≥ 5.2
Let's plug 5.2 into x for our length and width.
Length = 5x = 5(5.2) = 26 cm
Width = 5x - 4 = 5(5.2) - 4 = 26 - 4 = 22 cm
The smallest possible dimensions for the rectangle are, length = 26 cm and width = 22 cm
Different ways to make the number 15,638 with
hundreds, tens and ones are: <span>
156 hundreds, 3 tens and 8 ones
150 hundreds, 63 tens and 8 ones
141 hundreds, 161 tens and 28 ones
<span>we can write the numbers in thousands, hundreds, tens and ones
by using the place values. We use these ten numbers 0,1,2,3,4,5,6,7,8,9 along
with the concept of place value.</span></span>
Answer:
9 cm, 2 cm
or
6 cm , 3 cm
Step-by-step explanation:
There are two possibilities of the lengths of the sides of rectangle
