Answer:
Whats the question?
Step-by-step explanation:
Given:
Angle A is 4 degrees greater than the measure of Angle B. Both angles are complementary
Complementary angles have a sum of 90°
Angle A = x + 4° ; Angle B = x
x + 4° + x = 90°
2x = 90° - 4°
2x = 86°
x = 86° ÷ 2
x = 43° ANGLE B.
Angle A = x + 4° ⇒ 43° + 4 = 47°
Given:
Angle D is 5 times the measure of Angle E. These angles are supplementary. This means that their sum is 180°
Angle D = 5x ; Angle E = x
5x + x = 180°
6x = 180°
x = 180° ÷ 6
x = 30° Angle E.
Angle D = 5x = 5(30) = 150°
If T and V are complementary angles, their sum is 90°.
V + T = 90°
48° + (2X+10)° = 90° . . . . . . . substitute given information
2X + 58 = 90 . . . . . . . . . . . . .. collect terms
2X = 32 . . . . . . . . . . . . . . . . .. subtract 58
X = 16 . . . . . . . . . . . . . . . . . .. divide by 2
The value of X is 16.
WE need to complete the square on the x and y terms:-
25x^2 - 100x - 9y^2 - 90y = 350
25(x^2 - 4x + ) - 9(y^2 + 10x ) = 350 + 25( ) - 9( )
25(x^2 - 4x + 4 ) - 9(y^2 + 10x + 25) = 350 + 25(4) - 9(25)
25(x - 2)^2 - 9(y + 5)^2 =
25(x - 2)^2 - 9(y + 5)^2 = 225
---------------- -------------- --------
225 225 225
( x - 2)^2 (y + 5)^2
------------- - -------------- = 1 Answer
9 25
