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Tasya [4]
2 years ago
10

Sin^2x + sin2x +2cox^2x = 2

Mathematics
1 answer:
Effectus [21]2 years ago
5 0

Answer:

Step-by-step explanation:

sin^2 \ x + sin ^2 \ x + 2cos^ 2\ x = 2\\\\2sin^2 \ x  + 2 cos^2 \ x = 2\\\\2 ( sin^2 \ x + cos^2 \ x ) = 2 \\\\2 \times 1 = 2 \\\\2 = 2 \\\\LHS = RHS \\\\Hence \ proved.

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3 years ago
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If you recieved a score of 80% on an assignment, what is the ratio of correct answers to incorrect anwers?
ra1l [238]
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you can also simplyfy it, by dividing both numbers by 20:

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7 0
2 years ago
What is the solution for 5x^2-x+6=0
kati45 [8]

The easiest way to solve this problem is by using the Pythagorean theorem :D

Pythagorean theorem: [-b +- sqrt(b^2 - 4ac)]/2a

5 = a

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therefore, by plugging these values in!

[-(-1) +- sqrt((-1)^2 - 4(5)(6))]/2(5)

[1 +- sqrt(1 - 120)]/10

Oh so we're using imaginary numbers, so in this case you'll need to know that i = sqrt(-1), so keep this in mind (I can see why this was so difficult)

[1 +- sqrt(119)*i]10

answers:

( 1 + i*sqrt(119) ) / 10

( 1 - i*sqrt(119) ) / 10

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Answer:

Step-by-step explanation:

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8 0
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