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Whitepunk [10]
3 years ago
15

In quadrilateral ABDC, AB // CD. Which additional piece of information is needed to determine that ABDC is a parallelogram? over

line AB cong overline CD O overline AC cong overline BD OAB overline AB perp overline BD; overline CD perp overline BD

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
4 0

Answer:

AC is parallel to BD

Step-by-step explanation:

A parallelogram is a quadrilateral with two pairs of parallel sides.

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Answer: ok what is the qustion?

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You have 200 items that cost $20 and you are selling them at the price of $100.
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Your total profit is $13,000. First you bought the 200 items for $20 each. That costs $4,000. Then you sold $50 of the items at $100 each. That’s $5,000. So already you’re in the green. You’ve already made $1,000 profit. Then you sold the rest of the items at a 20% discount. 150 items multiplied by $80 is $12,000. $12,000 plus the $1,000 equals $13,000 total.

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Depenendent Event
DaniilM [7]

Answer:

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Step-by-step explanation:

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2 years ago
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For f(x)=4sin(x2) between x=0 and x=3, find the coordinates of all intercepts, critical points, and inflection points to two dec
telo118 [61]

Answer:

Intercepts:

x = 0, y = 0

x = 1.77, y = 0

x = 2.51, y = 0

Critical points:

x = 1.25, y = 4

x = 2.17 , y = -4

x = 2.8, y = 4

Inflection points:

x = 0.81, y = 2.44

x = 1.81, y = -0.54

x = 2.52, y = 0.27

Step-by-step explanation:

We can find the intercept by setting f(x) = 0

4sin(x^2) = 0

sin(x^2) = 0

x^2 = n\pi where n = 0, 1, 2,3, 4, 5,...

x = \sqrt(n\pi)

Since we are restricting x between 0 and 3 we can stop at n = 2

So the function f(x) intercepts at y = 0 and x:

x = 0

x = 1.77

x = 2.51

The critical points occur at the first derivative = 0

f^{'}(x) = 4cos(x^2)2x = 8xcos(x^2) = 0

xcos(x^2) = 0

x = 0 or

cos(x^2) = 0

x^2 = \frac{\pi}{2} + n\pi where n = 0, 1, 2, 3

x = \sqrt{\pi(n+1/2)}

Since we are restricting x between 0 and 3 we can stop at n =  2

So our critical points are at

x = 1.25, y = f(1.25) = 4sin(1.25^2) = 4

x = 2.17 , y = f(2.17) = 4sin(2.17^2) = -4

x = 2.8, y = f(2.8) = 4sin(2.8^2) = 4

For the inflection point, we can take the 2nd derivative and set it to 0

f^[''}(x) = 8(cos(x^2) - xsin(x^2)2x) = 8cos(x^2) - 16x^2sin(x^2) = 0

cos(x^2) = 2x^2sin(x^2)

tan(x^2) = \frac{1}{2x^2}

We can solve this numerically to get the inflection points are at

x = 0.81, y = f(0.81) = 4sin(0.81^2) = 2.44

x = 1.81, y = f(1.81) = 4sin(1.81^2) = -0.54

x = 2.52, y = f(2.52) = 4sin(2.52^2) = 0.27

3 0
3 years ago
I AM BEGGING, PLEASE HELP ME. CAN SOMEONE PLEASE HELP ME!
Temka [501]

Answer:

37.5

Step-by-step explanation:

180-75 = 105

180 is the sum of all the angle in a triangle

180-105 = 75

75/2 = x becuz the triangle is icoceles

=37/5

Hope this helps :) Giving me brainiest would help a lot :))

8 0
2 years ago
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