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shepuryov [24]
3 years ago
13

WIll give brainliest

Mathematics
2 answers:
lutik1710 [3]3 years ago
8 0
I need more context what are you asking for exactly I mean this gives information a bout some of the sixth amendment in the English bill of rights but you aren’t telling me what you want to know what should I be looking for
mojhsa [17]3 years ago
7 0

Answer:

Judges could reverse a trial verdict

Step-by-step explanation:

The appellate court will do one of the following:

Affirm the decision of the trial court, in which case the verdict at trial stands.

Reverse the decision to the trial court, in which case a new trial may be ordered.

Remand the case to the trial court.

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Tyler has 30 marbles 40% of his marbles are blue how many of his marbles are blue
rewona [7]

Answer:

12 marbles are blue.

Step-by-step explanation:

3 x 4 = 12, so 40 % of 30 is 12.

6 0
3 years ago
A rectangle in Quadrant I rotates 270° counterclockwise. In which quadrant will the transformation lie? A) Quadrant I B) Quadran
babymother [125]
Hi there!

The rectangle would progress from quadrant 1 to quadrant 2 90 degrees, then to quadrant 3 at 180 degrees, then finally quadrant 4 at 270 degrees. The answer is C) Quadrant IV

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
4 0
3 years ago
Please help me find the area
Vlad [161]

Answer:

25x^2 - 4

Step-by-step explanation:

and x times an x is x^2 so

25x^2 - 4

6 0
3 years ago
Uhh help?
Leni [432]
Hope you can read that okay

5 0
3 years ago
Let $abcdefgh$ be a cube of side length 5, as shown. let $p$ and $q$ be points on $\overline{ab}$ and $\overline{ae}$, respectiv
Anna [14]
Let's buils the intersection plane:
Point P is on AB and AP=2, then PB=3; point Q is on AE and AQ=1, then QE=4. Let P' be a point on CD such that CP'=2 and Q' be a point on the plane CDHG such that P'Q'=1 and P'Q' is perpendicular to CD. The line CQ' intersects HD at point R and the plane CPQR is intersection plane.
Consider triangles ΔCDR and ΔCP'Q', they are similar. So,
\frac{CP'}{CD}=  \frac{P'Q'}{RD}  \\  \frac{2}{5}  =\frac{1}{RD}  \\ RD=2.5,
so R is a midlepoint of the side HD (for details see picture).



5 0
4 years ago
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